Question

Solve the system. {3x+ 2y=8 {3x+3=y

Answer 1

Let's take this problem step-by-step:

Note:

'-- (1), -- (2), etc.' are equation markers used to show steps

First step, isolate all the variables to one side and constant to the other

 $3x + 2y = 8--(1)\\3x-y=-3--(2)$

Second step: (1) - (2)

 $(1) - (2)\\3x + 2y-(3x-y)=8-(-3)\\2y + y=11\\3y = 11\\y = \frac{11}{3} --(3)$

Third step: Plug (3)'s value of y into (2)

$(3)_.into_.(2)\\3x -\frac{11}{3} = -3\\3x = \frac{11}{3}-3\\ 3x = \frac{11-9}{3} \\3x = \frac{2}{3} \\x=\frac{2}{9}$

Answer: x = 2/9, y = 11/3

Hope that helps!

#LearnwithBrainly

Answer 2

Answer:

3x+ 2y=8  ⇒ ( 1 )

  3x+3=y  ⇒ ( 2 )

First, let us take the equation (1).

We can replace y with ( 3x + 3 ).

Solving the below expression let us find the value of x.

$3x + 2y = 8\\3x + 2 ( 3x + 3 ) = 8\\3x + 6x + 6 = 8\\9x + 6 = 8\\9x = 8 - 6\\9x = 2\\x = \frac{2}{9}$

And now let us take equation ( 2) to find the value of y.

For that let us replace x with 2/9.

Let us find it now.

$3x+3=y\\\\3*\frac{2}{9} +3=y\\ \\\frac{6}{9} +3=y\\ \\\frac{6}{9} +\frac{3}{1} =y\\\\\frac{6}{9} +\frac{3*9}{1*9} =y\\\\\frac{6}{9} +\frac{3*9}{1*9} =y\\\\\frac{6}{9} +\frac{27}{9} =y\\\\\frac{33}{9} =y\\\\\frac{11}{3} = y$