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artcher [175]
2 years ago
6

How to factorize 5x^2-20y^2​

Mathematics
2 answers:
Lilit [14]2 years ago
7 0

Answer:

Step-by-step explanation:

5x^2-20y^2\\=5(x^{2} -4y^2)\\=5[x^{2} -(2y)^2]\\=5(x+2y)(x-2y)

Lelu [443]2 years ago
6 0

Answer:

Step-by-step explanation:

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Step-by-step explanation: The "[" means that it is apart of the graph. The ")" means it is not apart of the graph.

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Answer:


Step-by-step explanation:

Given problems are absolute value problems, So we need to plug the values of given parameters and get the final result.

We have given here,

a =-2 , b = 3 ,  c = -4 and d = -6

Now we know that An absolute function always gives a positive value.

Let's apply this strategy in the given problems.

1. ║a+b║

Plug a= -2 and b = 3

We get, ║-2+3║=║1║= 1

2. 5║c+b║

Plug c= -4 and b=3

i.e.   5║-4 + 3║= 5║-1║=5×1 = 5

3. a+b║c║

Plug values a= -2 , b=3 and c=-4

i.e -2 +3║-4║ = -2 + 3×4 = -2 + 12 = 10

4. ║a+c║÷(-d)

i.e ║-2 + (-4)║÷(-6) = ║-6║÷(-6) = 6÷(-6) = -1

5. 3║a+d║+b

i.e 3║-2+(-6)║+3 = 3║-8║+3 = 3×8 +3 = 27

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Answer:

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Step-by-step explanation:

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Tasya [4]
He had $14.40 + $15 =39.40
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3 years ago
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