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3 years ago

Please someone help me with my homework thanks

Mathematics

2 answers:

anygoal [31]3 years ago

6 0

Answer:

whats your homework?

Step-by-step explanation:

lana [24]3 years ago

6 0

Answer:

what is it plsss mark BRAINLIEST

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Please help. 10 points and brainliest.

Snezhnost [94]

Answer:

$\frac{a^2}{b^2}$

Step-by-step explanation:

Apply the exponent rule $a^b*a^c=a^b+c$ to a

$a^4*a^-^2=a^4^-^2=a^2$

$b^3a^2b^-^5$

Apply the exponent rule to b

$b^3*b^-^5=b^3^-^5=b^-^2$

Apply the exponent rule $a^-^b=\frac{1}{a^b}$

$b^-^2=\frac{1}{b^2}=\frac{1}{b^2}a^2=\frac{a^2}{b^2}$

6 0

3 years ago

Find the surface area of the triangular prism

lesya692 [45]

The surface area of the triangular prism is 1664 square inches.

Explanation:

Given that the triangular prism has a length of 20 inches and has a triangular face with a base of 24 inches and a height of 16 inches.

The other two sides of the triangle are 20 inches each.

We need to determine the surface area of the triangular prism.

The surface area of the triangular prism can be determined using the formula,

$SA= bh+pl$

where b is the base, h is the height, p is the perimeter and l is the length

From the given the measurements of b, h, p and l are given by

$b=24$ , $h= 16$ , $l=20$ and

$p=20+20+24=64$

Hence, substituting these values in the above formula, we get,

$SA= (24\times16)+(64\times20)$

Simplifying the terms, we get,

$SA=384+1280$

Adding the terms, we have,

$SA=1664 \ square \ inches$

Thus, the surface area of the triangular prism is 1664 square inches.

6 0

3 years ago

The comprehensive strength of concrete is normally distributed with μ = 2500 psi and σ = 50 psi. Find the probability that a ran

VARVARA [1.3K]

Answer:

The probability that the diameter falls in the interval from 2499 psi to 2510 psi is 0.00798.

Step-by-step explanation:

Let's define the random variable, $X =$ "Comprehensive strength of concrete". We have information that $X$ is normally distributed with a mean of 2500 psi and a standard deviation of 50 psi (or a variance of 2500 psi). In other words, $X \sim N(2500, 2500)$ .

We want to know the probability of the mean of X or $\bar{X}$ that falls in the interval $[2499;2510]$ . From inference theory we know that :

$\bar{X} \sim N(2500, \frac{2500}{5}) \Rightarrow \bar{X} \sim N(2500,500)$

Now we can find the probability as follows:

$P(2499 \leq \bar{X} \leq 2510) \Rightarrow P(\frac{2499 - 2500}{500} \leq \frac{\bar{X} - 2500}{500} \leq \frac{2499 - 2500}{500} ) \Rightarrow\\\Rightarrow P(-0.002 \leq \frac{\bar{X} - 2500}{500} \leq 0.02 ) \Rightarrow P(-0.002 \leq Z \leq 0.02 )$