Question

Given the function h(x) = 3(5)x, Section A is from x = 0 to x = 1 and Section B is from x = 2 to x = 3. Part A: Find the average rate of change of each section. (4 points) Part B: How many times greater is the average rate of change of Section B than Section A? Explain why one rate of change is greater than the other. (6 points) (10 points)

Answer 1

Answer:

For section A, the average rate of change is 12. For section B, the average rate of change is 300. The average rate of change in Section B is greater than Section A by 25. The rate of change keeps on increasing because the slope of the function is increasing.

Step-by-step explanation:

Concept: For a function f(x), the rate of change is given by $\frac{f(x_{2})-f(x_{1}) }{x_{2}-x_{1} }$. Given function is h(x) = 3(5∧x).

For x = 0 to x = 1, the value of function would be f(0) = 3 to f(1) = 15.

The rate of change would be (15-3) / (1-0) = 12.

For x = 2 to x = 3, the value of function would be f(2) = 75 to f(3) = 375.

The rate of change would be (375-75) / (3-2) = 300.

The average rate of change in Section B is greater than Section A by

300 / 12 = 25.

Looking at the function, that is h(x) = 3(5∧x), we see that this function is an increasing function. The slope of an increasing function keeps on increasing with the value of x. The rate of increase is also a slope. That is why the rate keeps on increasing.

For more explanation, refer the following link:

brainly.com/question/525358

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