We are comparing maxima. From the graph we know that the max of one graph is +2 at x = -2. What about the other graph? Need to find the vertex to find the max.
Complete the square of <span>h(x) = -x^2 + 4x - 2:
</span>h(x) = -x^2 + 4x - 2 = -(x^2 - 4x) -2 = -(x^2 - 4x + 4 - 4) - 2 =-(x^2 - 4x + 4) -2+4 = -(x-2)^2 + 2 The equation describing this parabola is y=-(x-2)^2 + 2, from which we know that the maximum value is 2, reached when x = 2.
The 2 graphs have the same max, one at x = -2 and one at x = + 2.
