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2 years ago

Which of the following terms best describes a vertical line that the graph of a function approaches but never intersects

Mathematics

1 answer:

patriot [66]2 years ago

4 0

Answer: an asymptote is, essentially, a line that a graph approaches , but does not intersect.

Step-by-step explanation:

for example , in the following graph of y =1x y=1x the line approaches the x- axis (y=0) but never touches it

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At lunch, 8 friends share 6 sandwiches equally what fraction of a sandwich does each friend get?

zalisa [80]

Each friend would get 3/4 of a sandwich.

We take the 8 sandwiches and decide them by six. Then we get 0.75. Then we change it to fractions.

0.75. 75
——- x 100 ——- Then we simplify.
1. 100. And get 3/4

4 0

3 years ago

In Louisiana, the highest point of elevation is Driskill Mountain at 535 feet above sea level and the lowest point of elevation

jeyben [28]

535 + 8

The elevation difference is a total of 543 feet between Driskill Mountain and New Orleans.

4 0

3 years ago

Read 2 more answers

You select a marble without looking and then put it back. If you do this 3 times, what is the best prediction possible for the n

GenaCL600 [577]

Answer:

1 out of 3 times more likley but

Step-by-step explanation:

4 0

2 years ago

The total cost (in hundreds of dollars) to produce x units of a product is c(x) = (3x-2) / (8x+1), find the average cost for eac

olya-2409 [2.1K]

Answer:

a) $\frac{74}{10025}$

b) $\frac{3x-2}{x(8x+1)}$

c) $\frac{-24x^2+32x-2}{(8x^2+x)^2}$

Step-by-step explanation:

For total cost function $c(x)$ , average cost is given by $\frac{c(x)}{x}$ i.e., total cost divided by number of units produced.

Marginal average cost function refers to derivative of the average cost function i.e., $\left ( \frac{c(x)}{x} \right )'$

Given: $c(x)=\frac{3x-2}{8x+1}$

Average cost = $\frac{c(x)}{x}=\frac{3x-2}{x(8x+1)}$

At x = 50 units,

$\frac{c(50)}{50}=\frac{150-2}{50(400+1)}=\frac{148}{50(401)}=\frac{74}{10025}$

Average cost = $\frac{c(x)}{x}=\frac{3x-2}{x(8x+1)}$

Marginal average cost:

Differentiate average cost with respect to $x$

Take $f=3x-2\,,\,g=8x^2+x$

using quotient rule, $\left ( \frac{f}{g} \right )'=\frac{f'g-fg'}{g^2}$

Therefore,

$\left ( \frac{c(x)}{x} \right )'=\left ( \frac{3x-2}{8x^2+x} \right )'\\=\left ( \frac{3(8x^2+x)-(16x+1)(3x-2)}{(8x^2+x)^2} \right )\\=\frac{24x^2+3x-48x^2-3x+32x+2}{(8x^2+x)^2}\\=\frac{-24x^2+32x-2}{(8x^2+x)^2}$

3 0

3 years ago

A line has a y-intercept and a slope of 0. What is the line’s equation?

Gnom [1K]

The answer is y= -1

When the slope is 0, we refer to the line as a constant function. In slope intercept form, the line is equal to y = mx + b

"m" is the slope, and "b" is the y-intercept.

Let's replace those in the function.

y = 0*x - 1

0 multiplied by anything is 0

y = 0 - 1

y = -1

6 0

3 years ago