Ask question

Ask question

All categories

2 years ago

10

wo competing companies are having sales on projectors. Projector #MD375 has a retail price of $1,200. The Office Spot is adverti

sing #MD375 for 20% off, while Office & Beyond has stated they will match any competitor’s advertised special and take an additional 15% off of the competitor’s advertised price. How much money is saved by purchasing the projector from Office & Beyond instead of the Office Spot?

1 answer:

pshichka [43]2 years ago

8 0

The amount of money that is saved by purchasing the projector at Office and beyond is $144.

<h3>How much money is saved?
</h3>

The first step is to determine the price of the projector at The Office spot.

Discounted price : (1 - 0.20) x $1200

0.80 x $1200 = $960

The second step is to determine the price of the projector at the Office and Beyond.

Discounted price : (1 - 0.15) x $960 = $816

Difference in price : 960 - 816 = $144

To learn more about how to calculate discounts, please check: brainly.com/question/26061308

#SPJ1

You might be interested in

Solve for x. Use the quadratic formula. 3x2+7x+3=0 Enter the solutions, in simplified radical form, in the boxes. x = or x =

BartSMP [9]

Answer:

Step-by-step explanation:

X= (-7+radical 13)/6

X=(-7-radical 13)/6

5 0

3 years ago

Solve x + 3y = 9. 3x – 3y = –13

Sloan [31]

$Question \ 1) \ x + 3y = 9$

$
x=9-3y
 
$ $|Subtract \ 3y \ from \ both \ sides|$

$Question \ 2) \ 3x - 3y = -13$

$
3(x-y)=-13
 
$ $|Factor \ out \ the \ common \ term \ 3|$

$x-y= \dfrac{13}{3}$ $|Divide \ both \ sides \ by \ 3|$

$x=- \dfrac{13}{3}+y$ $|Add \ y \ to \ both \ sides|$

$x=y- \dfrac{13}{3}$ $|Regroup \ terms|$

7 0

3 years ago

What is the square root of 9/16ths

spayn [35]

The answer is 3/4ths. If you have any questions please ask

3 0

3 years ago

Write 91.5% as a decimal

Lyrx [107]

Answer:

0.915

Step-by-step explanation:

move the decimal two to the left and take a the percentage

5 0

3 years ago

Read 2 more answers

You measure 44 textbooks' weights, and find they have a mean weight of 51 ounces. Assume the population standard deviation is 11

elena-14-01-66 [18.8K]

Answer: (47.51, 54.49)

Step-by-step explanation:

Confidence interval for population mean is given by :-

$\overline{x}\pm z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}$

, where n= sample size .

$\sigma$ = population standard deviation.

$\overline{x}$ = sample mean

$z_{\alpha/2}$ = Two -tailed z-value for ${\alpha$ (significance level)

As per given , we have

$\sigma=11.8\text{ ounces}$

$\overline{x}=51 \text{ ounces}$

n= 44

Significance level for 95% confidence = $\alpha=1-0.95=0.05$

Using z-value table ,

Two-tailed Critical z-value : $z_{\alpha/2}=z_{0.025}=1.96$

Now, the 95% confidence interval for the true population mean textbook weight will be :-

$51\pm (1.96)\dfrac{11.8}{\sqrt{44}}\\\\=51\pm(1.96)(1.7789)\\\\=51\pm3.486644\approx51\pm3.49\\\\=(51-3.49,\ 51+3.49)\\\\=(47.51,\ 54.49)$

Hence, the 95% confidence interval for the true population mean textbook weight. : (47.51, 54.49)

8 0

3 years ago