The expression in company B represents that is is in arithmetic progression where first term is 42000 and common difference is 1800 . So we have to use the formula of sum of n terms which is

Where a is the first term, n is the nth term, d is the common difference
On substituting there values,we will get

= 15(84000+52200) = 15*136200 =2043000
And for company A, it is

Difference between them =2043000-2002500= 40500
So the correct option is the second option .
Answer:
See the proof below.
Step-by-step explanation:
Assuming this complete question: "For each given p, let Z have a binomial distribution with parameters p and N. Suppose that N is itself binomially distributed with parameters q and M. Formulate Z as a random sum and show that Z has a binomial distribution with parameters pq and M."
Solution to the problem
For this case we can assume that we have N independent variables
with the following distribution:
bernoulli on this case with probability of success p, and all the N variables are independent distributed. We can define the random variable Z like this:
From the info given we know that
We need to proof that
by the definition of binomial random variable then we need to show that:


The deduction is based on the definition of independent random variables, we can do this:

And for the variance of Z we can do this:
![Var(Z)_ = E(N) Var(X) + Var (N) [E(X)]^2](https://tex.z-dn.net/?f=%20Var%28Z%29_%20%3D%20E%28N%29%20Var%28X%29%20%2B%20Var%20%28N%29%20%5BE%28X%29%5D%5E2%20)
![Var(Z) =Mpq [p(1-p)] + Mq(1-q) p^2](https://tex.z-dn.net/?f=%20Var%28Z%29%20%3DMpq%20%5Bp%281-p%29%5D%20%2B%20Mq%281-q%29%20p%5E2)
And if we take common factor
we got:
![Var(Z) =Mpq [(1-p) + (1-q)p]= Mpq[1-p +p-pq]= Mpq[1-pq]](https://tex.z-dn.net/?f=%20Var%28Z%29%20%3DMpq%20%5B%281-p%29%20%2B%20%281-q%29p%5D%3D%20Mpq%5B1-p%20%2Bp-pq%5D%3D%20Mpq%5B1-pq%5D)
And as we can see then we can conclude that 
8minutes-2minutes=6minutes
6×80 copies = 480 copies
There are three different type
Explain
In math , there are three different type , they are arithmetic progression ( Ap) , Geometric progression and Harmonic
Arithmetic Progression - When a fix constant is added to each number except the first number.
For example : 2,4,6,8,10..... Here 2 is added each time to get the next number.
2. Geometric Progression - When a fix constant is multiplied to each number except the first number.
For example : 2,6,18,54.... Here 3 is multiplies each time to get first number.
3. Harmonic - a harmonic progression (or harmonic sequence) is a progression formed by taking the reciprocals of an arithmetic progression.
For example : 1/2 , 1/4 , 1/6, 1/8 ....
Answer:
c. 2b - 3
Step-by-step explanation:
Simplify the following:
-2 b + 4 + 4 b - 7
Grouping like terms, -2 b + 4 + 4 b - 7 = (4 b - 2 b) + (4 - 7):
(4 b - 2 b) + (4 - 7)
4 b - 2 b = 2 b:
2 b + (4 - 7)
4 - 7 = -3:
Answer: 2 b + -3