By equation of motion we have v = u + at
Where u = Initial velocity, v = final velocity, t = time taken and a = acceleration
Here v = 141 m/s, u = 17.7 m/s and t = 6 s
On substitution we will get
141 = 17.7+ 6a
So, a = (141-17.7)/6 = 20. 55 m/
Aceeleration = 20. 55 m/
along north direction.
kilograms or mass hope this helps
Answer:
B type ii supernova is the right answer
It's on your exam boards specification or just google it. the foundation paper will have the same equations as higher, but higher just has more.