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adelina 88 [10]
2 years ago
7

At what point does a rubber band have the most elastic potential energy? Explain.

Physics
1 answer:
madam [21]2 years ago
8 0

Answer:

You input potential (stored) energy into the rubber band system when you stretched the rubber band back. Because it is an elastic system, this kind of potential energy is specifically called elastic potential energy. ... When the rubber band is released, the potential energy is quickly converted to kinetic (motion) energy.

Explanation:

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A 75-kg piano is hoisted on a crane and delivered throughout the window of a 6th story apartment (20 meters above ground). What
ipn [44]

Answer:

P = 14700 J

Explanation:

Given that,

Mass of a piano, m = 75 kg

It is delivered throughout the window of a 6th story apartment which is 20 m above the ground.

We need to find the potential energy of the piano. It is given by :

P = mgh

Putting all the values,

P = 75 kg × 9.8 m/s² × 20 m

P = 14700 J

So, the potential energy of the piano is 14700 J.

7 0
3 years ago
a skier is gliding along 3.0 m/s on horizontal, frictionless snow. he suddenly starts down a 10 degrees incline. his speed at th
Elza [17]
... find length
(way 1) determine acceleration using force
only force act on skier is mg vertically. spilt vector we get force along the incline = mgsin(10) and f= ma so
ma = mgsin(10) or a = gsin(10)
a (along the incline)= gsin(10) = 10sin(10) = 1.74
v^2 = u^2 + 2as
15^2 = 3^2 + 2(1.74)s
s = 62.06 m

(way 2) using conservation of energy
energy (KE+PE) on top = energy at bottom
0.5m3^2 + mgh = 0.5m15^2 +0
h (height of incline) = (112.5 - 4.5)/10 = 19.8 m
length of incline = h/sin(10) = 62.2 m ; trigonometry

... find time
s = (u+v)t/2
t = 2s/(u+v) = 2(62.2)/(3+15) = 6.91 s
4 0
3 years ago
Which list places different units of matter in the correct sequence from largest to smallest
weqwewe [10]

Answer:

What do you mean?

6 0
2 years ago
Read 2 more answers
CHEGG You stretch a spring with spring constant k = 1.2x104 N/m to extend 6.0 cm away from its equilibrium position. How much do
lubasha [3.4K]

Answer:

The elastic potential energy of the spring change during this process is 21.6 J.    

Explanation:

Given that,

Spring constant of the spring, k=1.2\times 10^4\ N/m

It extends 6 cm away from its equilibrium position.

We need to find the elastic potential energy of the spring change during this process. The elastic potential energy of the spring is given by the formula as follows :

E=\dfrac{1}{2}kx^2\\\\E=\dfrac{1}{2}\times 1.2\times 10^4\times (0.06)^2\\\\E=21.6\ J

So, the elastic potential energy of the spring change during this process is 21.6 J.

4 0
3 years ago
If a car changes ita velocity from 32km/hr to 54km/hr in 8.0 seconds, what is its acceleration
Komok [63]
3.75kmper squ hr
acc = (v - u) /t
=(54-32)/8
=22/8
= 3.75kmhr^-2
4 0
3 years ago
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