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sesenic [268]
2 years ago
8

Find the equation that results from completing the square in the following equation. x^2−20x+75=0

Mathematics
1 answer:
Ymorist [56]2 years ago
8 0

The equation that results from completing the square in the following equation. x^2−20x+75=0 is (x+2)^2 = 10

<h3>What is completing the squares method for solving the quadratic equations in one variable?</h3>

The method "completing the squares", as per the name suggests, try to make the quadratic equation of the form such that the x variable is totally covered in single squared term, as the square of a linear expression in x.

GIven;

x^2−20x+75=0

Subtract 75 from each side

x^2−20x+75 - 75 = -75

Take the coefficient of x

20

Divide by 2

10

Square it

100

Add it to each side

x^2 +5x + 100 = -75 + 100

(x+2)^2 = 10

Take the square root of each side

x+2 = 10

x = 8

Learn more about this concept here;

brainly.com/question/23364759

#SPJ1

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3(x - 25) < $100.  We're not req'd to solve this.


8 0
3 years ago
3. Solve 2log4y - log4 (5y - 12) = 1/2<br>​
Ilia_Sergeevich [38]

Answer:

y =  4  or y = 6

Step-by-step explanation:

2log4y - log4 (5y - 12) = 1/2

​2log_4(y) - log_4(5y-12) = log_4(2)           apply law of logarithms

log_4(y^2) + log_4(1/(5y-12)) = log_4(/2)    apply law of logarithms

log_4(y^2/(5y-12)) = log_4(2)                     remove logarithm

y^2/(5y-12) = 2                                            cross multiply

y^2 = 10y-24                                                  rearrange and factor

y^2 - 10y + 24 = 0

(y-4)(y-6) = 0

y= 4 or y=6

4 0
3 years ago
HELP QUICK PLS HELP QUICK PLS
PilotLPTM [1.2K]

Answer:

<h3>I THINK ITS • (4X2+32X+64-π(x2+2x+1))</h3>

Step-by-step explanation:

i hope it helps :)

7 0
3 years ago
Consider the following scenario describing Mr. Smith's math students: A list pairs math grades with student heights.
KonstantinChe [14]

Answer:

No, Because students who have the same math grade can be different heights

Step-by-step explanation:

C is the answer DO NOT PICK D

You have the put the correct input and output IN ORDER so D is the wrong answer

8 0
3 years ago
Read 2 more answers
Prove that root 7 is irrational by the method of contradiction
Alchen [17]

Let assume that \sqrt7 is a rational number. Therefore it can be expressed as a fraction \dfrac{a}{b} wherea,b\in\mathbb{Z} and \text{gcd}(a,b)=1.

\sqrt7=\dfrac{a}{b}\\\\7=\dfrac{a^2}{b^2}\\\\a^2=7b^2

This means that a^2 is divisible by 7, and therefore also a is divisible by 7.

So, a=7k where k\in\mathbb{Z}

(7k)^2=7b^2\\\\49k^2=7b^2\\\\7k^2=b^2

Analogically to a^2=7b^2 ------- b^2 is divisible by 7 and therefore so is b.

But if both numbers a and b are divisible by 7, then \text{gcd}(a,b)=7 which contradicts our earlier assumption that \text{gcd}(a,b)=1.

Therefore \sqrt7 is an irrational number.

8 0
4 years ago
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