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MissTica
1 year ago
15

How many apples? Help me please, thanks so much

Mathematics
1 answer:
Anna71 [15]1 year ago
3 0

The number of Apples that were in the given fruit salad is approximately; 2170 Apples.

<h3>How to work with ratio questions?</h3>

We are given the ratio of apples to oranges as;

A:O = 31:11

Now, we are told that there are 2940 apples and oranges in total.

Thus, the fractions of apples and oranges of the total will be;

Apple fraction = 31/(31 + 11) = 31/42

Orange Fraction = 11/42

Thus;

Number of Apples = (31/42) * 2940

Number of Apples = 2170 Apples

Read more about ratios at; brainly.com/question/2784798

#SPJ1

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If you spin the spinner 10 times, what is the best prediction possible for the number of times it will land on blue
Alexus [3.1K]

Answer:

It depends on how many other colors there are

Step-by-step explanation:

8 0
3 years ago
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Perform the following computations.You may use13≈0.333333,34= 0.75 and100301= 0.332226.(i). Compute13+34by using five significan
White raven [17]

Answer:

a. 1.0833

Absolute Error = 0.416667

Relative Error = 1.250002

b. 0.0011070

Absolute Error = 0.0011070

Relative Error = 0.003321

Step-by-step explanation:

Given

1/3 = 0.333333

3/4 = 0.75

100/301 = 0.332226

a.

1/3 + 3/4

= 0.333333 + 0.75

= 1.083333

= 1.0833 ------ Approximated to 5 significant digits

Absolute Error = |Real Value - Estimated Value|

Relative Error = Absolute Error/Real Value

Assume 1/3 to be the real value and 3/4 to be the estimated value

Absolute Error = |0.333333 - 0.75|

Absolute Error = |-0.416667|

Absolute Error = 0.416667

Relative Error = 0.416667/0.333333

Relative Error = 1.250002

b.

1/3 - 100/301

= 0.333333 - 0.332226

= 0.001107

= 0.0011070 ----- Approximated to 5 significant digits

Assume 1/3 to be real value and 100/301 to be estimated value

Absolute Error = 0.333333 - 0.332226

Absolute Error = 0.0011070

Relative Error = 0.0011070/0.333333

Relative Error = 0.003321

Absolute and relative errors are approximation errors and they are due to the discrepancy between an exact value and some approximation to them.

The absolute error is the magnitude of the difference between the exact value and the approximation. The relative error is the absolute error divided by the magnitude of the exact value

4 0
3 years ago
A mountain bike originally priced at $960.00 is up for sale at a discount of 14%. What is the price of the mountain bike after t
PilotLPTM [1.2K]

Answer:

$825.60

Step-by-step explanation:

Since the price of it is $960.00, it means that it's 100%.

100% = 960

1% = 960 ÷ 100 = 9.6

14% = 9.6 x 14 = 134.40

Since they asked for after the discount, deduct the price of the discount with the original price.

Mountain bike after 14% discount =

960 - 134.40 = 825.60

7 0
3 years ago
Read 2 more answers
It takes 22 hours for a hosepipe with a flow of 12 litres per minute to fill a swimming pool. How long will it take if its flow
Monica [59]

Answer:

t2 = 52.8 hours

it will take 52.8 hours if its flow is reduced to 5 litres per minute.

Step-by-step explanation:

The volume of the swimming pool can be written as;

Volume V = flow rate × time

V = R×t

V = R1×t1 = R2×t2

R1×t1 = R2×t2

t2 = R1×t1/R2 ........1

Given;

Flow rate R1 = 12 litres per minute

Flow rate R2 = 5 litres per minute

time t1 = 22 hours

Substituting the given values into equation 1;

t2 = R1×t1/R2 = 12×22/5

t2 = 52.8 hours

it will take 52.8 hours if its flow is reduced to 5 litres per minute.

3 0
3 years ago
A linear sequence starts a+3b a+7b a+11b the 2nd term has value 19 the 5th term has value 67 work out the values of a and b
alekssr [168]

Answer:

a = -9

b = 4

Step-by-step explanation:

Given

Sequence: a+3b, a+7b, a+11b

2nd term = 19

5th term = 67

Required

Find a and b

First, the 5th term needs to be calculated;

Using formula for Arithmetic Progression (AP), the formula goes thus

T_n = T_1 + (n - 1)d

Where n = 5

T_1 = a + 3b ------------ FIrst term

d = T_2 - T_1 or T_3 - T_2 --- Difference between two successive terms

d = a + 7b - (a + 3b)

d = a + 7b -a - 3b

d = a - a + 7b - 3b

d = 4b

So, T_n = T_1 + (n - 1)d becomes

T_5 = a + 3b + (5 - 1)4b

T_5 = a + 3b + (4)4b

T_5 = a + 3b + 16b

T_5 = a + 19b

Now that we have values for 2nd and 5th term;

From the second, T2 = 19 and T5 = 67

This gives

a + 7b = 19 --- Equation 1

a + 19b = 67 ---- Equation 2

Make a the subject of formula in (1)

a = 19 - 7b

Substitute these values in equation 1

a + 19b = 67 becomes

19 - 7b + 19b = 67

19 + 12b = 67

Collect like terms

12b= 67 - 19

12b = 48

Divide both sides by 12

\frac{12b}{12} = \frac{48}{12}

b = 4

Recall that b = 4

Substitute a = 19 - 7b and nothing will hire

a = 19 - 7(4)

a = 19 - 28

a = -9

Hence, the values of a and b are -9 and 4 respectively.

5 0
3 years ago
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