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Marina CMI [18]

2 years ago

8

Joe got a bonus of $1,600.20 based on a certain percent of his sales for the year, which was $22,860. What percent of his sales

for the year was the bonus?

1 answer:

devlian [24]2 years ago

3 0

0.07 hope this helps

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Solve this problem please <br> x/3+6-2x=-6

Nikolay [14]

Answer:

36/5

Step-by-step explanation:

x/3 + 6 -2x = -6

multiply the whole equation by 3 to get rid of the denominator of the first x term.

x+18-6x = -18

move x terms to one side and numerical terms to the other, subtract 18 from both sides in this case

x+18-6x-18=-18-18

x-6x = -36

simplify

-5x = -36

divide both sides by -5 to isolate x

x = -36/-5

=36/5

3 0

3 years ago

Vending machines can be adjusted to reject coins above and below certain weights. The weights of legal U.S. quarters have a norm

tigry1 [53]

Answer: The percentage of legal quarters will be rejected by the vending machine = 2.275%

Step-by-step explanation:

Given: The weights of legal U.S. quarters have a normal distribution with a mean of 5.67 grams and a standard deviation of 0.07 gram.

Let x be the weights of legal U.S. quarters .

Required probability: $P(x5.81)$

$=P(\dfrac{x-\mu}{\sigma}\dfrac{5.81-5.67}{0.07})\\\\=P(z2)\approx0.02275 \ \ \ [By\ P-value\ calculator]$

The percentage of legal quarters will be rejected by the vending machine = 2.275%

5 0

2 years ago

The sum ∫2−2() ∫52()−∫−1−2() can be written as a single integral in the form ∫() determine and

kow [346]

We have

$\displaystyle \int_{-2}^2 f(x) \, dx - \int_{-2}^{-1} f(x) \, dx = \int_{-1}^2 f(x) \, dx$

so that

$\displaystyle \int_{-2}^2 f(x) \, dx + \int_2^5 f(x) \, dx - \int_{-2}^{-1} f(x) \, dx \\\\ ~~~~~~~~~~~~ = \int_{-1}^2 f(x) \, dx + \int_2^5 f(x) \, dx \\\\ ~~~~~~~~~~~~ = \boxed{\int_{-1}^5 f(x) \, dx}$

6 0

1 year ago

What is the proportion of 22/3

Rudiy27

Answer:

not to sure but is it 733.333333333333%

Step-by-step explanation:

4 0

2 years ago

the length of a rectangle is 2 cm less than five times the width. the area of the rectangle is 16 cm^2. find the length and widt

ahrayia [7]

<span>length = L
</span>width = w

L = (5w-2) cm

$w(5w-2)=16 \\ 5w^2-2w-16=0 \\ D=b^2-4ac=(-2)^2-4*5*(-16)=324 \\ w_{1,2}= \frac{-bб \sqrt{D} }{2a} \\ w_1= \frac{2- \sqrt{324} }{2*5}= \frac{2-18}{10}=-1.6 \ \ \O \\ w_2= \frac{2+18}{10}=2 cm$

width = 2 cm
length = 5w-2 = 5*2-2 = 8 cm

8 0

3 years ago