Answer:
potato<-100
print(potato)
sqrt(potato)
potato<-potato*2
print(potato)
Explanation:
The complete question is as follows
Create a variable called potato whose value corresponds to the number of potatoes you’ve eaten in the last week. Or something equally ridiculous. Print out the value of potato.
Calculate the square root of potato using the sqrt() function. Print out the value of potato again to verify that the value of potato hasn’t changed.
Reassign the value of potato to potato * 2.
Print out the new value of potato to verify that it has changed
The question was answered using R programming language.
At line 1, I assumed that I ate 100 potatoes in the previous week.
So, potato = 100
At line 2, the value of potato is printed as 100.
At line 3, the square root of potato is calculated using sqrt function: Square for of 100 = 10
At line 4,the initial value of potato is doubled and stored in potato variable. 100 * 2 = 200
At line 5, the new value of potato is printed: 200.
Answer:
the mean time I was wondering if you have any questions or need any further information please contact me at the mean time I was
The all purpose one will work or you could use type C I believe.
Answer:
Given:
efficiency of the turbine, 
= 65% = 0.65
available gross head, 
= 45 m
head loss, 
= 5 m
Discharge, Q = 
Solution:
The nozzle is 100% (say)
Available power at the inlet of the turbine, 
is given by:
(1)
where
= density of water = 997 
acceleration due to gravity, g = 
Using eqn (1):
Also, efficency, is given by:
The answer is b, I hope this helps you
