Answer
Statically determinate beams are those beams in which the unknown reaction forces are equal or less than the equilibrium equation.
As shown in figure 1 in which reaction forces are 3 and we have 3 equilibrium equation so beam is determinate.
Statically indeterminate beams are those beams in which unknown reaction force are more than the equilibrium equation.
As shown in figure 2 in which reaction forces are 6 and we have 3 equilibrium equation so beam is indeterminate.
Answer:
Fractional conversion=0.749
Percentage by which the other reactant is in excess=16.56%
extent = 56.23 mol/s
Explanation:
reaction
molar composition of the product stream:
= 51.7%
HBr = 17.3 %
when you add these two compositions you don't get 100% (69%) so there is also ethylene in the product stream.
= 100% - 69% = 31%
We are going to suppose a flow rate in the product stream of 100 mol/s. Although you have a flow rate for the feed stream since you don't know the molar composition in the entrance is easier suppose a molar flow in the outlet.
with this information we can estimate the number of moles in the product stream as:
MF= total molar flow.
HBr =17.3 mol/s
= 31 mol/s
The stoichiometry for this reaction is 1: 1. With this information we can estimate the moles of each reagent in the feed stream. To produce 51.7 mol of we needed 51.7 moles of HBr and
respectively.
= 82.7 mol
with this we can see that the limit reagent in this reaction is HBr.
82.7 mol of need the same number of mol of HBr but there is just 69 moles of this.
The molar composition in the inlet is:
HBr = = 45.4%
= 100% - 45.4% = 54.51%
Fractional conversion of HBr (FC) =
percentage of in excess =
=16.56%
b. The extent of reaction (e) is defined as:
where n indicate the moles of a compound in the inlet (in) and in outlet (out) respectively and v is the stoichiometric coefficient for that compound in the reaction. It can be negative if it's a reagent or positive if it's a product.
In this case we have 165 mol/s a flow rate in the inlet. Assuming that the composition in the inlet and the fractional conversion are the same we have.
mol HBr (inlet) = 165 mol/s * 45.4% = 75.04 mol
mol HBr_{out}=
v=-1