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sesenic [268]
3 years ago
7

Que a state properties of Sounds ] 1 laws of replactions of light 2 2​

Engineering
1 answer:
Vanyuwa [196]3 years ago
5 0

Answer:

A sound is an energy source, much like electricity, heat or light. That makes a loud ringing noise when you hit a bell. Now put your finger on the bell after you’ve hit it, rather than just listening to the bell. You can feel it shaking and this motion or moving, i.e., the body’s to and fro motion is termed as vibration.

Sound is a vibration that passes through the medium in the form of longitudinal waves. It implies that sound waves are waves wherein the particles of the medium vibrate parallel to the direction of wave propagation. Sound forms are known as mechanical waves because they require a propagating medium. The medium may be

Solids

Liquids

Gases

Properties of sound

Frequency or pitch

Frequency is the number of cycles of periodic compression and rarefaction which occur every second as the wave propagates via the medium.

The human ear’s interpretation of the sound level within the range of human hearing is called the pitch.

The higher the sound frequency, the higher the pitch is and a lower frequency means a lower pitch.

Speed

The speed at which the sound waves travel via the medium is called sound speed. The speed of sound for different mediums is different. Sound moves in solids faster, as the atoms in a solid are packed tightly.

Amplitude or Loudness

The loudness determines the amplitude of the sound waves.

The sound amplitude is a measure of the magnitude of the overall sound disturbance.

The amplitude is a measure of the vibrational energy.

More energetic vibration is responsible for a greater amplitude.

Timbre

Timbre is the property used to distinguish between sounds of the same frequency.

Timbre based on what substance the sound is created from.

Reflection of sound

As sound waves encounter a solid or light surface, it bounces back into the same medium. It is termed as sound reflection. Sound waves obey the laws of reflection, like light waves.

Explanation:

<h2>●♡ <em>jess </em><em>bregoli</em><em> </em> ♡●</h2>

#<em>k</em><em>e</em><em>e</em><em>p</em><em> </em><em>learning</em><em>!</em><em>!</em>

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3 years ago
An Ideal gas is being heated in a circular duct as while flowing over an electric heater of 130 kW. The diameter of duct is 500
Assoli18 [71]

Answer: The exit temperature of the gas in deg C is 32^{o}C.

Explanation:

The given data is as follows.

C_{p} = 1000 J/kg K,   R = 500 J/kg K = 0.5 kJ/kg K (as 1 kJ = 1000 J)

P_{1} = 100 kPa,     V_{1} = 15 m^{3}/s

T_{1} = 27^{o}C = (27 + 273) K = 300 K

We know that for an ideal gas the mass flow rate will be calculated as follows.

     P_{1}V_{1} = mRT_{1}

or,         m = \frac{P_{1}V_{1}}{RT_{1}}

                = \frac{100 \times 15}{0.5 \times 300}  

                = 10 kg/s

Now, according to the steady flow energy equation:

mh_{1} + Q = mh_{2} + W

h_{1} + \frac{Q}{m} = h_{2} + \frac{W}{m}

C_{p}T_{1} - \frac{80}{10} = C_{p}T_{2} - \frac{130}{10}

(T_{2} - T_{1})C_{p} = \frac{130 - 80}{10}

(T_{2} - T_{1}) = 5 K

T_{2} = 5 K + 300 K

T_{2} = 305 K

           = (305 K - 273 K)

           = 32^{o}C

Therefore, we can conclude that the exit temperature of the gas in deg C is 32^{o}C.

8 0
3 years ago
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