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3 years ago

14

the odometer in Mr Washington's car does not work correctly the odometer recorded 13.2 miles for his last trip to the hardware s

tore but he knows the distance traveled is 15 Mi what is the percent error

1 answer:

Nonamiya [84]3 years ago

3 0

12 percent is the error.

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Show me how to do this on paper i need it right now

postnew [5]

Answer:

Step-by-step explanation:

32 x 10 = 320

32 x 4 = 128

320 + 128 = 448

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2 years ago

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A chocolate chip cookie recipe calls for 6 cups of chopped nuts and 8 cups of chocolate chips. When Gregory made a batch of thes

Radda [10]

Answer:

He did not

Step-by-step explanation:

if you put 6: 8 in a fraction 6/8, it doesn't have any relationship with 9/12

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3 years ago

. A recent report in a women magazine stated that the average age for women to marry in the United States is now 25 years of age

Setler [38]

Answer: 0.0136

Step-by-step explanation:

Given : Mean : $\mu=25$

Standard deviation : $\sigma=3.2$

Sample size : $n=50$

The formula to calculate the z-score :-

$z=\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}$

For x = 24

$z=\dfrac{24-25}{\dfrac{3.2}{\sqrt{50}}}=-2.21$

The p-value = $P(z\leq-2.21)= 0.0135526\approx0.0136$

Hence, the probability that the sample mean age for 50 randomly selected women to marry is at most 24 years = 0.0136

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3 years ago

i f N(-7,-1) is a point on the terminal side of ∅ in standard form, find the exact values of the trigonometric functions of ∅.

Natali [406]

Answer:

$sin\ \varnothing = \frac{-1}{10}\sqrt 2$

$cos\ \varnothing = \frac{-7}{10}\sqrt 2$

$tan\ \varnothing = \frac{1}{7}$

$cot\ \varnothing = 7$

$sec\ \varnothing = \frac{-5}{7}\sqrt 2$

$csc\ \varnothing = -5\sqrt 2$

Step-by-step explanation:

Given

$N = (-7,-1)$ --- terminal side of $\varnothing$

Required

Determine the values of trigonometric functions of $\varnothing$ .

For $\varnothing$ , the trigonometry ratios are:

$sin\ \varnothing = \frac{y}{r}$ $cos\ \varnothing = \frac{x}{r}$ $tan\ \varnothing = \frac{y}{x}$

$cot\ \varnothing = \frac{x}{y}$ $sec\ \varnothing = \frac{r}{x}$ $csc\ \varnothing = \frac{r}{y}$

Where:

$r^2 = x^2 + y^2$

$r = \sqrt{x^2 + y^2$

In $N = (-7,-1)$

$x = -7$ and $y = -1$

So:

$r = \sqrt{(-7)^2 + (-1)^2$

$r = \sqrt{50$

$r = \sqrt{25 * 2$

$r = \sqrt{25} * \sqrt 2$

$r = 5 * \sqrt 2$

$r = 5 \sqrt 2$

<u>Solving the trigonometry functions</u>

$sin\ \varnothing = \frac{y}{r}$

$sin\ \varnothing = \frac{-1}{5\sqrt 2}$

Rationalize:

$sin\ \varnothing = \frac{-1}{5\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$sin\ \varnothing = \frac{-\sqrt 2}{5*2}$

$sin\ \varnothing = \frac{-\sqrt 2}{10}$

$sin\ \varnothing = \frac{-1}{10}\sqrt 2$

$cos\ \varnothing = \frac{x}{r}$

$cos\ \varnothing = \frac{-7}{5\sqrt 2}$

Rationalize

$cos\ \varnothing = \frac{-7}{5\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$cos\ \varnothing = \frac{-7*\sqrt 2}{5*2}$

$cos\ \varnothing = \frac{-7\sqrt 2}{10}$

$cos\ \varnothing = \frac{-7}{10}\sqrt 2$

$tan\ \varnothing = \frac{y}{x}$

$tan\ \varnothing = \frac{-1}{-7}$

$tan\ \varnothing = \frac{1}{7}$

$cot\ \varnothing = \frac{x}{y}$

$cot\ \varnothing = \frac{-7}{-1}$

$cot\ \varnothing = 7$

$sec\ \varnothing = \frac{r}{x}$

$sec\ \varnothing = \frac{5\sqrt 2}{-7}$

$sec\ \varnothing = \frac{-5}{7}\sqrt 2$

$csc\ \varnothing = \frac{r}{y}$

$csc\ \varnothing = \frac{5\sqrt 2}{-1}$

$csc\ \varnothing = -5\sqrt 2$

3 0

3 years ago

oksian1 [2.3K]

Answer:

-9

Step-by-step explanation:

f(2) - f(4) / 2-4

[2²+3(2)] - [4²+3(4)] / -2

(10 - 28) / 2

= -18/2

= -9

6 0

3 years ago

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