Using the asymptote concept, we have that:
- The vertical asymptote is x = 9.
- The horizontal asymptote is y = 3.
- The end behavior is that as
.
<h3>What are the asymptotes of a function f(x)?</h3>
- The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator.
- The horizontal asymptote is the value of f(x) as x goes to infinity, as long as this value is different of infinity.
In this problem, the function is:
For the vertical asymptote, we have that:
x - 9 = 0 -> x = 9.
For the horizontal asymptote:
Hence, the end behavior is that as .
More can be learned about asymptotes at brainly.com/question/16948935
#SPJ1
1 meter = 1000 millimeters
Answer:
position: (-6, -4)
range: 6
Step-by-step explanation:
The equation is that of a circle centered at (-6, -4) with a radius of √36 = 6. We presume that the "position" is that of the circle's center, and the "range" is the radius of the circle.
___
The standard form equation of a circle with center (h, k) and radius r is ...
(x -h)^2 +(y -k)^2 = r^2
Matching parts of the equation, we find ...
h = -6, k = -4, r = √36 = 6.
Answer: a^2x^2+9x^2+13x+6a
Step-by-step explanation:
(a^2+9) x^2+ 13x +6a
x^2(a^2+9)+13x+6a
Expand:x^2(a^2+9): a^2 x^2+9^2
x^2 a^2 +x^2*9
a^2 x^2+9x^2
a^2 x^2+9x^2+13x+6a
