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kkurt [141]
2 years ago
5

Find the locus of a point P which moves so that the sum of squares of squares of its distance A(3,0)and B(-3,0) is 4 times the d

istance between A and B​
Mathematics
1 answer:
Sonbull [250]2 years ago
3 0

Based on the calculations, the equation for the locus of these points is equal to x² + y² = 9.

<h3>How to find the locus of a point?</h3>

First of all, we would determine the distance between points A and B as follows:

Distance = √[(x₂ - x₁)² + (y₂ - y₁)²]

Distance = √[(-3 - 3)² + (0 - 0)²]

Distance = √[-9² + 0]

Distance = √81

Distance = 9.

Four (4) times the distance between points A and B​ is given by:

Distance = 9 × 4

Distance = 36.

Translating the word problem into a mathematical expression, we have:

a² + b² = 36

Also, from the distance formula we have:

a = √[(h + 3)² + (k - 0)²]

a² = h² + 6h + 9 + k²    

Similarly, b² is given by:

b = √[(h - 3)² + (k - 0)²]

b² = h² - 6h + 9 + k²

Equating the equations, we have:

a² + b² = 36

h² + 6h + 9 + k² + h² - 6h + 9 + k² = 36

2h² + 2k² = 36 - 18

2h² + 2k² = 18

Dividing both sides by 2, we have:

h² + k² = 9   ⇒ x² + y² = 9.

Read more on locus of a point here: brainly.com/question/23824483

#SPJ1

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It would mean a lot.
LUCKY_DIMON [66]
First, subtract y2 - y1 to find the vertical distance. Then, subtract x2 - x1 to find the horizontal distance.

Formula to find distance given two points.

Square root (X2 - X1)^2 + (Y2 - Y1)^2

Xa Ya Xb Yb
A = (3, -4) B = (-1, 3)

Xa goes into X2 and Xb goes into X1

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(-4 - 3)^2

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= 8.06

The error was Drako had (3 - 4)^2 when it should have been (3 - (-4))^2 because a positive is subtracting a negative.
6 0
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