Toni adds the numbers <br>what is toni's mistake

Please help! Find the equation of the line and I will mark as brainliest IF answer is right. <3

Hoochie [10]

<h3>Answer: y = (3/4)x + 13/4</h3>

This is the same as writing y = 0.75x + 3.25

slope is 3/4 = 0.75

y intercept is 13/4 = 3.25

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Explanation:

One marked point on this line is (-3,1)

Another point is at (1,4)

Let's find the slope of the line through these two points.

m = (y2-y1)/(x2-x1)

m = (4-1)/(1-(-3))

m = (4-1)/(1+3)

m = 3/4

m = 0.75

Now let's use point slope form to find the equation of the line

y - y1 = m(x - x1)

y - 1 = 0.75(x - (-3))

y - 1 = 0.75(x + 3)

y - 1 = 0.75x + 2.25

y = 0.75x + 2.25 + 1

y = 0.75x + 3.25

If you wanted, you can convert those decimal values to fraction form

0.75 = 75/100 = 3/4
3.25 = 325/100 = 13/4

That means the equation

y = 0.75x + 3.25

is the same as

y = (3/4)x + 13/4

4 0

2 years ago

Quadrilateral CDEF is reflected across the x-axis and translated 3 units left to create quadrilateral GHJK .

PilotLPTM [1.2K]

Answer- KG⎯∥JH⎯

the given figure is a trapezium in which CF||DE

Reflection of figure CDEF and shifting it by 3 units does not change the shape of the figure but changes only its position in the x-y plane.

so, the shape of the figure GHJK will be same as that of CDEF.

so sides, KG⎯∥JH⎯

6 0

3 years ago

Find b for the following right angled triange where a=5 and c=13

lilavasa [31]

You would use the Pythagorean there on which is a^2+b^2=c^2, from there you plug int what they gave you and solve for b, and b=12

4 0

3 years ago

If g(x)=4x^2-16 we’re shifted 9 united to the right and 1 down, what would the new equation be?

Inessa05 [86]

Shown in the graph

<h2>Explanation:</h2>

Using graph tools we can graph the function:

$g(x)=4x^2-16$

which is the red graph shown below. As you can see, this is a parabola. The rule for vertical and horizontal shifts is as follows:

$Let \ c \ be \ a \ positive \ real \ number. \ \mathbf{Vertical \ and \ horizontal \ shifts} \\ in \ the \ graph \ of \ y=f(x) \ are \ represented \ as \ follows:$

$\bullet \ Vertical \ shift \ c \ units \ \mathbf{upward}: \\ h(x)=f(x)+c \\ \\ \bullet \ Vertical \ shift \ c \ units \ \mathbf{downward}: \\ h(x)=f(x)-c \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ right \ \mathbf{right}: \\ h(x)=f(x-c) \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ left \ \mathbf{left}: \\ h(x)=f(x+c)$