The answer is B because its 9 hundred and thousandths is the smallest place
35
the ratio for the two is 5:7 and you want to find _:49. to get from 7 to 49 you multiply the 7 by 7. because you did that to one side you have to do the same to the other and multiply 5 by 7 which gives you 35
The answer is either 
or 
To solve: Let's solve your equation step-by-step.
5x2+5x−x2−x=2004
Step 1: Simplify both sides of the equation.
4x2+4x=2004
Step 2: Subtract 2004 from both sides.
4x2+4x−2004=2004−2004
4x2+4x−2004=0
Step 3: Use quadratic formula with a=4, b=4, c=-2004.
x=
−b±√b2−4ac
/2a
x=
−4±√32080
/8
or
First solve the quadratic as you would an equation, so you will get two real zeroes p and q so that (x-p)(x-q)=0 is another way of expressing the quadratic. All quadratics can be represented graphically by a parabola, which could be inverted. When the x² coefficient is negative it’s inverted. If the coefficient of x² isn’t 1 or -1 divide the whole quadratic by the coefficient so that it takes the form x²+ax+b, where a and b are real fractions. The curve between the zeroes will be totally below the x axis for an upright parabola, and totally above for an inverted parabola. This fact is used for inequalities. An inequality will be <, ≤, > or ≥. This makes it easy to solve the inequality. If the position of the curve between the zeroes is below the axis then outside this interval it will be above, and vice versa. So we’ve defined three zones. x
q, and p
Answer:
Graph y = 2x
Step-by-step explanation:
First, let's get the equation into standard form. Distribute the 2 on the right.
Next, we want the variable "y" to be alone, so we at 4 to both sides.
That is our equation in standard y = mx + b form. "m" is our slope, while "b" is our y-intercept. Above , we don't have a value for b, therefore the line passes through the origin.
We do, however, have a slope, which can be thought of as 
or rise over run. To represent this, we can rewrite our slope as:
Meaning in each interval, the line goes up by 2 units, and moves forward by 1.
