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Over [174]
1 year ago
13

If three farmers share some bags of fertilizers in the ratio 3:4:5.if the smallest share is 18 bags.what is the largest share

Mathematics
1 answer:
nika2105 [10]1 year ago
8 0

Answer:

30

Step-by-step explanation:

Sum of the ratios = 3 + 4 + 5 = 12

Smallest share = 18 bags

Ratio of the smallest share = 3

Let the largest share = x

From the question

18 ------------ 3

x --------------5

Cross multiply

3x = 18 × 5

Dividing bothsides by 3

X = 18 × 5/ 3

X = 90 / 3

X = 30

Therefore.

The largest share = 30

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Answer:

<u>Question (a)</u>

Midpoint of a line segment:

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Given:

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\implies \textsf{midpoint of }JL=\left(\dfrac{-2+4}{2},\dfrac{2+0}{2}\right)=(1,1)

Given:

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\implies \textsf{midpoint of }MK=\left(\dfrac{3-1}{2},\dfrac{7-5}{2}\right)=(1, 1)

<u>Question (b)</u>

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\textsf{slope }m=\dfrac{y_2-y_1}{x_2-x_1}

Given:

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\implies \textsf{slope of }JL=\dfrac{0-2}{4+2}=-\dfrac13

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  • K = (-1, -5)

\implies \textsf{slope of }MK=\dfrac{-5-7}{-1-3}=3

\textsf{slope of }JL \times \textsf{slope of }MK=-\dfrac13 \times3=-1

Hence segments JL and MK are perpendicular

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A plumber charges an initial amount,x, to make a house call plus an hourly rate,y, for the time he is working.A 1-hour job costs
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Step-by-step explanation:

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