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Answer
The mean of three numbers x1,x2,x3 can be obtained by a calculus. The first step of the algorithm is
1)
In order to obtain the median, maximun and minumun of x1, x2 and x3, we can compare x1 and x2. The smaller of those numbers will be compared to x3 and, if x3 is even smaller, then x3 is the minimun, the other small number is the median, and the remaining number is the maximun. Otherwise, we compare x3 with the bigger number to find median and maximun. To summarize:
2) compare x1 with x2. The bigger of the two numbers will be called '<em>s</em>' (for small) and the smaller will be called '<em>b</em>' (from big).
3) compare x3 with <em>s</em>. The smaller of this subset will be the minimun of the entire set of 3 elements.
4) Check if x3 is the minimun, in that case, <em>s </em>is the median, because <em>s</em> is between x3 and <em>b. </em>We also conclude that <em>b</em> is the maximun
5) if x3 in not the minimun, then compare it with <em>b.</em> The bigger element between the two of them will be the maximun of the set, and the smaller one will be the median.
I hope it helps you!
Answer:
H in terms of c is H = 5c³.
Step-by-step explanation:
Given that:
H = 40 and c = 2
H varies directly to the cube of c.
Which means that,
H ∝ c³
Let,
k be the proportionality constant.
H = kc³
Putting H=40 and c=2
Dividing both sides by 8,
Now,
H in terms of c.
H = 5c³
Hence,
H in terms of c is H = 5c³.