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2 years ago

Select the correct answer.

Mathematics

1 answer:

fomenos2 years ago

7 0

The inverse function of f(x) is $f^{-1}(x) = \sqrt{x - 6}$ and the domain is x > 6

<h3>How to determine the inverse function?</h3>

The function is given as:

f(x) = x^2 + 6

Rewrite as:

y = x^2 + 6

Swap x and y

x = y^2 + 6

Subtract 6 from both sides

y^2 = x - 6

Take the square root

$y = \sqrt{x - 6}$

Rewrite as:

$f^{-1}(x) = \sqrt{x - 6}$

Hence, the inverse function of f(x) is $f^{-1}(x) = \sqrt{x - 6}$ and the domain is x > 6

Read more about inverse function at:

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Line segmentAB has vertices A(−3, 4) and B(1, −2) . A dilation, centered at the origin, is applied to AB⎯⎯⎯⎯⎯ . The image has ve

zysi [14]

Answer:

The scale factor is

$\frac{1}{3}$

Step-by-step explanation:

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We could also compare:

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3 years ago

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An athlete earns $350,000 each year. If his team makes the play-offs, he will earn a 15% bonus. What will be his total earnings

Komok [63]

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3 years ago

Find the quotient of these complex numbers.

stich3 [128]

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Answer:

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3 years ago

What does the quadratic function f(x)=x^2-10x+9 look like when it is rewritten in the form f(x) = a (x-h) + k

Tatiana [17]

ANSWER

When $f(x)=x^2-10x+9$ is written in the form $f(x)=a(x-h)^2+k$ , it looks like $f(x)=(x-5)^2-16$

EXPLANATION

To write $f(x)=x^2-10x+9$ in the form $f(x)=a(x-h)^2+k$ , we have to complete the squares.

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4 years ago

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almond37 [142]

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3 years ago