Question

Select the correct answer.

Answer 1

The inverse function of f(x) is $f^{-1}(x) = \sqrt{x - 6}$ and the domain is x > 6

How to determine the inverse function?

The function is given as:

f(x) = x^2 + 6

Rewrite as:

y = x^2 + 6

Swap x and y

x = y^2 + 6

Subtract 6 from both sides

y^2 = x - 6

Take the square root

$y = \sqrt{x - 6}$

Rewrite as:

$f^{-1}(x) = \sqrt{x - 6}$

Hence, the inverse function of f(x) is $f^{-1}(x) = \sqrt{x - 6}$ and the domain is x > 6

Read more about inverse function at:

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