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suter [353]
2 years ago
12

A tour company charges a given price per ticket based on the number, n, of people who take the tour. the maximum number of peopl

e who are allowed to take the tour is 35. the price per ticket is $20 unless more than 10 people take the tour. if more than 10 people take the tour, the price per ticket is given by the expression: 20- n-10/2 b. harper goes on a tour where the ticket price is $10.50. how many people went on this tour? solve algebraically.
Mathematics
1 answer:
UkoKoshka [18]2 years ago
3 0

Harper goes on a tour where the ticket price is $10.50 along with 29 people according to the given expression. Solving the given expression for 'n' results in the required number.

<h3>How to solve an algebraic expression?</h3>

Solving an expression algebraically involves basic operations like addition, subtraction, multiplication, and division.

  • In the expression, add/subtract the constant terms on both sides
  • Multiply/divide the coefficient of the variable on both sides
  • Solve for the variable.

<h3>Calculation:</h3>

Given that,

A tour company charges a given price per ticket based on the number 'n' of people who take the tour.

The maximum number of people who are allowed to take the tour is 35. I.e., n ≤ 35.

The price per ticket is $20 for n < 10 people and the price per ticket is given by the expression 20-(n-10)/2 for n > 10 people.

Harper goes on a tour where the ticket price is $10.50.

Since the price is less than $20, so the number of people who went on this tour is known by the expression 20-(n-10)/2 for n > 10 people.

So, solving the given expression:

20-(n-10)/2 = $10.50

-(n-10)/2 = 10.50 - 20

-(n-10)/2 = -9.5

(n-10) = 9.5 × 2

n -10 = 19

∴ n = 19 + 10 = 29

Therefore, 29 people went on this tour for a ticket price of $10.50.

Learn more about solving an expression here:

brainly.com/question/723406

#SPJ4

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<span>I note that this problem starts out with "Which is a factor of ... "  This implies that you were given several answer choices.  If that's the case, it's unfortunate that you haven't shared them.

I thought I'd try finding roots of this function using synthetic division.  See below:

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Please use " ^ " to denote exponentiation.  Thanks.

Possible zeros of this poly are factors of 35:  plus or minus 1, plus or minus 5, plus or minus 7.  Use synthetic division; determine whether or not there is a non-zero remainder in each case.  If none of these work, form rational divisors from 35 and 6 and try them:  5/6, 7/6, 1/6, etc.

Provided that you have copied down the function 
</span>f(x) = 6x^4 – 21x^3 – 4x^2 + 24x – 35  properly, this approach will eventually turn up 1 or 2 zeros of this poly.  Obviously it'd be much easier if you'd check out the possible answers given you with this problem.

By graphing this function, I found that the graph crosses the x-axis at 7/2.  There is another root.

Using synth. div. to check whether or not 7/2 is a root:

         ___________________________
7/2   /   6    -21    -4    24    -35
                   21      0   -14     35           
        ----------- ------------------------------
           6        0     -4    10       0

Because the remainder is zero, 7/2 (or 3.5) is a root of the polynomial.  Thus, (x-3.5), or (x-7/2), is a factor.

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