3 years ago

What is the solution to the linear equation?

1 answer:

4 0

x=-5 ___________________

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kiruha [24]

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Proportional.

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Vedmedyk [2.9K]

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kupik [55]

Answer:

(a) 0.873 (b) 0.007 (c) 0.715 (d) 0.277 (e) 1.25 and 1.09

Step-by-step explanation:

The probability that the random variable X takes the value x is given by P(X=x) = $25Cx 0.05^x0.95^{25-x}$ . Then,

(a) $P(X\leq) = (25C0)(0.05^0)(0.95^{25}) + (25C1)(0.05^1)(0.95^{24}) + (25C2)(0.05^2)(0.95^{23})= 0.873$

(b) $P(X\geq5) = 1-P(X\leq4) = 1 - (0.873 + (25C3)(0.05^3)(0.95^{22}) + (25C4)(0.05^4)(0.95^{21})) = 1 - (0.873 + 0.12) = 0.007$

(c) $P(1\leqX\leq4) = (25C1)(0.05^1)(0.95^{24}) + (25C2)(0.05^2)(0.95^{23}) + (25C3)(0.05^3)(0.95^{22}) + (25C4)(0.05^4)(0.95^{21}) = 0.715$

(d) $P(X=0) = (25C0)(0.05^0)(0.95^{25}) = 0.277$

(e) E(X) = np = (25)(0.05) = 1.25 and $Sd(X) = \sqrt{Var(X)} = \sqrt{np(1-p)} = 1.09$

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3 years ago