Answer:
See explanation.
Step-by-step explanation:
2) Your written answer is correct, y = x +4
3) Slope of perpendicular line: 5/2
y=mx+b
4 = (5/2)(4) + b
4 = 10 + b
b = -6
So, y=(5/2)x - 6
4) Slope of perpendicular line: 1
y=mx+b
5 = (1)(4) + b
5 = 4 + b
b = 1
So, y = x + 1
7) Slope of perpendicular line: 3/4
y=mx+b
4 = (3/4)(4) + b
4 = 3 + b
b = 1
So, y = (3/4)x + 1
8) Slope of perpendicular line: 1/4
y=mx+b
-2 = (1/4)(0) + b
b = -2
So, y = (1/4)x - 2
So, pretend this is your x-axis and y-axis:
I
I
(-2,7) • I
I
I • (2, 5)
I
I
I
I
_________________I____________________
I
I
I
TO GET FROM POINT (-2, 7) TO POINT (2, 5), WE MOVE DOWN 2 AND OVER 4, SO THE SLOPE IS -1/2. IF WE FOLLOW THAT SLOPE AND MOVE DOWN 1 AND OVER 2 FROM THE FIRST POINT OF (-2, 7), WE WILL LAND ON A POINT LOCATED AT (0, 6), WHICH WOULD BE THE "Y-INTERCEPT". WE WERE JUST ABLE TO CALCULATE THE SLOPE OF THE LINE AND THEN USE THE SLOPE TO FIND THE INTERCEPT. SO, THE "SLOPE-INTERCEPT" FORM OF THE EQUATION FOR THIS LINE IS:
y = -1/2x + 6
TO RE-WRITE THIS IN STANDARD FORM, WE JUST WANT TO MOVE THE X VARIABLE OVER TO THE LEFT WITH THE Y VARIABLE, SO:
y = -1/2x + 6
+1/2x + 1/2x
1/2x + y = 6 .... and that is your answer!
Answer:
The answer is: D
Step-by-step explanation:
