72? If I’m reading that right?
Answer:
The 99% confidence interval for the population mean reduction in anxiety was (1.2, 8.6).
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 27 - 1 = 26
99% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 26 degrees of freedom(y-axis) and a confidence level of
. So we have T = 2.7787.
The margin of error is:

In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 4.9 - 3.7 = 1.2.
The upper end of the interval is the sample mean added to M. So it is 4.9 + 3.7 = 8.6.
The 99% confidence interval for the population mean reduction in anxiety was (1.2, 8.6).
Answer:
there are agario clans now?
Step-by-step explanation:
To check which of the quotients is correct, multiply 43 times 20 and add the remainder. The result must be equal to 876.
First, notice that 20 times 43 equals 860.
A)
The remainder is 17. 860 + 17 = 877, which is not equal to 876.
B)
The remainder is 16. 860 + 16 = 876, which is equal to 876.
C)
The remander is 7. 860 + 7 = 867, which is not equal to 876.
D)
The remainder is 6. 860 + 6 = 866, which is not equal to 876.
Since 20*43 + 16 = 876, then the correct quotient is shown in option B:
876 ÷ 43 = 20 r 16
I think the answer is -100