Answer:
a. autotriploid of species A: 63 chromosomes
b. autotetraploid of species B: 96 chromosomes
c. allotriploid from species A and B: 1) 66 chromosomes and 2) 69 chromosomes
Explanation:
<u>For a.</u>
this species will have 3 haploid sets of chromosomes ('tri' means 3)
one haploid set = 21
21 × 3 = 63 chromosomes
<u>For b.</u>
this species will have 4 haploid sets of chromosomes ('tetra' means 4)
one haploid set = 24
24 × 4 = 96 chromosomes
<u>For c.</u>
there are two ways to do this:
1) two sets of chromosomes from species A and one from species B
42 + 24 = 66 chromosomes
2) one set of chromosomes from species A and two from species B
21 + 48 = 69 chromosomes
Hope that answers the question, have a great day!
Answer and Explanation:
My first response would be that it is not a good strategy to speculate things negatively in the very begining even when you have not tried it. We can definitely go for alternative drugs in case it doesn't fit to Jim's metabolic functioning and physiology. However, it is also possible that the drug would help Jim. Everybody is different when it comes to side effects of a particular drug. Some people even don't show any side effects for one particular drug whereas others show mild or significant concerns. Therefore, I would suggest her to reconsider her decision and try chlorpromazine as prescribed. After all, it is Schizophrenia and you cannot simply ignore it. Such negligence could worsen the situation for Jim and you all.
I think they have the answer to this online regents answer and a non regents answer
Shock Treatment (or Fish Fry) Presently several hundred feet of electrified canal water is all that stands between the most advanced front of Asian carp and a free run to the open waters of Lake Michigan.
Hope this helps :)
If p = frequency of A and q = frequency of a, then assuming H-W equilibrium we have
p + q = 1 ⇒ q = 1 - p = 1 - 0.55 = 0.45
Then the expected frequency of the heterozygous genotype Aa is 2pq = 2 • 0.55 • 0.45 = 0.495.
