Two compounds containing six carbon atoms on treatment with <span>either with BH</span>₃<span> in THF followed by H</span>₂<span>O</span>₂<span> /OH</span>⁻<span> (OR) with H</span>₂O <span>/ Hg</span>²⁺<span> / H</span>₃O⁺ gives the same products.
The two alkynes, their two different types of reactons and products are given below,
Answer:
5.81L
Explanation:
N1 = 1.70 moles
V1 = 3.80L
V2 = ?
N2 = 2.60 moles
Mole - volume relationship,
N1 / V1 = N2 / V2
V2 = (N2 × V1) / N1
V2 = (2.60 × 3.80) / 1.70
V2 = 9.88 / 1.70
V2 = 5.81 L
The volume of the gas is 5.81L
Answer:
Mole percent of water in azeotrope is 69%
Explanation:
Clearly, the azeotrope consists of water and perchloric acid.
So, 72% perchloric acid by mass means 100 g of azeotrope contains 72 g of perchloric acid and 28 g of water.
Molar mass of water = 18.02 g/mol and molar mass of perchloric acid = 100.46 g/mol
So, 72 g of perchloric acid = 
of perchloric acid = 0.72 mol of perchloric acid
Also, 28 g of water = 
of water = 1.6 mol of water
Hence total number of mol in azeotrope = (1.6+0.72) mol = 2.32 mol of azeotrope
So, mole percent of water in azeotrope = [(moles of water)/(total no of moles)]
%
Mole percent of water = 
% = 69%
Answer:3.
Explanation:when performing trace analyses and the analyte may adsorb to the glass.
