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charle [14.2K]
2 years ago
7

* Do you think odor is a property? Explain your ideas.

Chemistry
1 answer:
damaskus [11]2 years ago
7 0

Answer:

This might be simply as matter of convenience. It is now well known that different molecules have one of several smells. The sensation of smell is produced when the odor-causing molecule binds to certain sites (called receptors) high up in the nose.

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What element is most likely to form a diatomic molecule?
Harman [31]
Bromine (Br) is the only element listed that is a diatomic element. I believe that Bromine is going to be your answer.
5 0
3 years ago
Read 2 more answers
how does a decrease in potential energy during a chemical rwaction relate to the temperature of the surroundings​
blondinia [14]

Answer: If the potential energy of the reaction system decreases, then kinetic energy in the surroundings increases and the temperature of the surroundings rises

Explanation:

3 0
3 years ago
A compound contains only nitrogen and oxygen and has a formula mass of 44.02. What is the formula of the compound
ch4aika [34]
N₂O

N = 14.01 amu
O ≈ 16 amu

14.01 × 2 = 28.02 ; 2 Nitrogen

44.02 - 28.02 = 16 ; 1 Oxygen

Check

28.02 + 16 ≈ 44.02amu
8 0
3 years ago
The elements chlorine and iodine have similar chemical properties<br> because they
Anton [14]

Answer:

They are both halogens and have the same number of electrons on their outer shell.

Any element with 7 electrons in the outermost shell will have similar properties. Thus other elements in the same column of the periodic table as chlorine will have similar properties.

<u><em>If you liked my answer, please mark me brainliest!!!</em></u>

8 0
2 years ago
Consider the equation:
Dmitry [639]

Answer:1. Rate=k[CHCl_3]^1[Cl_2]^\frac{1}{2}

2. The rate constant (k) for the reaction is 3.50M^\frac{-1}{2}s^{-1}

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

rate=k[CHCl_3]^x[Cl_2]^y

k= rate constant

x = order with respect to CHCl_3

y = order with respect to Cl_2

n = x+y= Total order

1. a) From trial 1: 0.0035=k[0.010]^x[0.010]^y  (1)

From trial 2: 0.0069=k[0.020]^x[0.010]^y   (2)

Dividing 2 by 1 :\frac{0.0069}{0.035}=\frac{k[0.020]^x[0.010]^y}{k[0.010]^x[0.010]^y}

2=2^x,2^1=2^x therefore x=1.

b)  From trial 2: 0.0069=k[0.020]^x[0.010]^y   (3)

From trial 3: 0.0098=k[0.020]^x[0.020]^y   (4)

Dividing 4 by 3:\frac{0.0098}{0.0069}=\frac{k[0.020]^x[0.020]^y}{k[0.020]^x[0.010]^y}

1.4=2^y,2^{\frac{1}{2}}=2^y therefore y=\frac{1}{2}

rate=k[CHCl_3]^1[Cl_2]^\frac{1}{2}

2. to find rate constant using trial 1:

0.0035=k[0.010]^1[0.010]^\frac{1}{2}  

k=3.50M^\frac{-1}{2}s^{-1}

5 0
3 years ago
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