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ElenaW [278]
2 years ago
5

3

Mathematics
1 answer:
Serjik [45]2 years ago
8 0

Step-by-step explanation:

=  \frac{ \frac{3}{x - 2} - 5 }{2 -  \frac{4}{x - 2} }

=  \frac{ \frac{3 - 5.(x - 2)}{x - 2} }{ \frac{2.(x - 2) - 4}{x - 2} }

=  \frac{ \frac{3 - 5.(x - 2)}{ \cancel{x - 2}} }{ \frac{2.(x - 2) - 4}{ \cancel{x - 2} }}

=  \frac{3 - 5.(x - 2)}{2.(x - 2) - 4}

=  \frac{3 - 5x + 10}{2x - 4 - 4}

=  \frac{ - 5x + 13}{2x - 8}

=  \frac{13 - 5x}{2x - 8}

The answer is D.

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frutty [35]

Answer:

y=\dfrac{3x}{e}+\dfrac{4}{e}

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Step-by-step explanation:

to find the tangent line we need to find the derivative of the function g(x).

g(x) =e^{x^3}

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this the equation of the slope of the curve at any point x and it also the slope of the tangent at any point x. hence, g'(x) can be denoted as 'm'

to find the slope at (-1,1/e) we'll use the x-coordinate of the point i.e. x = -1

m =3 (-1)^{2} e^{(-1)^{3}}\\m =3e^{-1}\\m=\dfrac{3}{e}

using the equation of line:

(y-y_1)=m(x-x_1)

we'll find the equation of the tangent line.

here (x1,y1) =(-1,1/e), and m = 3/e

(y-\dfrac{1}{e})=\dfrac{3}{e}(x+1)\\y=\dfrac{3x}{e}+\dfrac{3}{e}+\dfrac{1}{e}\\

y=\dfrac{3x}{e}+\dfrac{4}{e}

this is the equation of the tangent at point (-1,1/e)

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Morgarella [4.7K]

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Step-by-step explanation:

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lukranit [14]

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Arlecino [84]

Answer:

31043.09

Step-by-step explanation:

Kinda feel bad for the last person who answered! They were way off but still you need to learn from your mistakes! Welp this answer is STRAIGHT OFF THE BACK from delta MATH! So this IS correct! If this helped click the stars and the heart to help fellow students, educators, etc. Understand this answer is for certain correct! I would add the steps but there is alot!

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20. Solve 3(5x − 4) &lt; 15x.<br> All Real Numbers<br> x&gt;-4 <br>x&lt;4<br>no solution ​
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