Answer:
Step-by-step explanation:
Radius = r = 3 in.
Height = h = 2 in.
<u>Volume:</u>
![\sf Volume \ of \ the \ cylinder = \pi r^2 h\\\\V = (3.14)(3)^2(2)\\\\V =(3.14)(9)(2)\\\\V = (3.14)(18)\\\\V = 56.5 \ in.^3\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Csf%20Volume%20%5C%20of%20%5C%20the%20%5C%20cylinder%20%3D%20%5Cpi%20r%5E2%20h%5C%5C%5C%5CV%20%3D%20%283.14%29%283%29%5E2%282%29%5C%5C%5C%5CV%20%3D%283.14%29%289%29%282%29%5C%5C%5C%5CV%20%3D%20%283.14%29%2818%29%5C%5C%5C%5CV%20%3D%2056.5%20%5C%20in.%5E3%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
Answer:
by how much degrees should the heat be reduced in the last 5 minutes of banking
Answer:
<u>A</u> He should ask his students to know what they prefer
Step-by-step explanation:
2x^3y+18xy-10x^2y-90y
= 2xy(x^2 + 9)- 10y(x^2 + 9)
= (x^2 + 9)(2xy - 10y)
= (x^2 + 9) 2y(x - 5)
= 2y (x^2 + 9) (x - 5)
Start by finding the area of each smaller right triangle.
Right triangle area = (1/2)hb -> h = height & b = base
b = 4 & h = 3
(1/2)(4)(3) = 6
6*2 = 12 (there are two right triangles)
The area of the entire triangle is 12yd^2
