Answer: i’m not sure if it’s just simplifying or factoring. but for simplifying it equals. 1/8 or .125
Explanation: calculator
20
Step-by-step explanation:
Step 1:
Let the number be 50 and to find 40% of 50 is given interms of expression as follows
To express the percentage the following strategy is used
Eg: 40% = ![40/100](https://tex.z-dn.net/?f=40%2F100)
∴ To express 40% of 50 is
![(40/100)*50](https://tex.z-dn.net/?f=%2840%2F100%29%2A50)
Step 2:
On simplification the above expression we could get
![0.4*50](https://tex.z-dn.net/?f=0.4%2A50)
= 20
Answer:
3) ![\sqrt{5}](https://tex.z-dn.net/?f=%5Csqrt%7B5%7D)
4)![5\sqrt{13}](https://tex.z-dn.net/?f=5%5Csqrt%7B13%7D)
Step-by-step explanation:
distance between two points:
![d = \sqrt{(x_{2}-x_{1})^{2}+ (y_{2}-y_{1})^{2}}](https://tex.z-dn.net/?f=d%20%3D%20%5Csqrt%7B%28x_%7B2%7D-x_%7B1%7D%29%5E%7B2%7D%2B%20%28y_%7B2%7D-y_%7B1%7D%29%5E%7B2%7D%7D)
we have:
3) (6, -2), (8, -3)
![x_{1} = 6](https://tex.z-dn.net/?f=x_%7B1%7D%20%3D%206)
![y_{1} =-2](https://tex.z-dn.net/?f=y_%7B1%7D%20%3D-2)
![x_{2} = 8](https://tex.z-dn.net/?f=x_%7B2%7D%20%3D%208)
![y_{2} =-3](https://tex.z-dn.net/?f=y_%7B2%7D%20%3D-3)
so we have:
![d =\sqrt{(8-6)^{2}+ (-3-(-2))^{2}}\\\\d =\sqrt{(2)^{2}+ (-1)^{2}}\\\\d = \sqrt{4+ 1}\\\\d=\sqrt{5}](https://tex.z-dn.net/?f=d%20%3D%5Csqrt%7B%288-6%29%5E%7B2%7D%2B%20%28-3-%28-2%29%29%5E%7B2%7D%7D%5C%5C%5C%5Cd%20%3D%5Csqrt%7B%282%29%5E%7B2%7D%2B%20%28-1%29%5E%7B2%7D%7D%5C%5C%5C%5Cd%20%3D%20%5Csqrt%7B4%2B%201%7D%5C%5C%5C%5Cd%3D%5Csqrt%7B5%7D)
4) (7,-8), (-8, 2)
![x_{1} = 7](https://tex.z-dn.net/?f=x_%7B1%7D%20%3D%207)
![y_{1} =-8](https://tex.z-dn.net/?f=y_%7B1%7D%20%3D-8)
![x_{2} =-8](https://tex.z-dn.net/?f=x_%7B2%7D%20%3D-8)
![y_{2} =2](https://tex.z-dn.net/?f=y_%7B2%7D%20%3D2)
![d =\sqrt{(-8-7)^{2}+ (2-(-8))^{2}}\\\\d =\sqrt{(-15)^{2}+ (10)^{2}}\\\\d = \sqrt{225+ 100}\\\\d=\sqrt{325}\\\\d=5\sqrt{13}](https://tex.z-dn.net/?f=d%20%3D%5Csqrt%7B%28-8-7%29%5E%7B2%7D%2B%20%282-%28-8%29%29%5E%7B2%7D%7D%5C%5C%5C%5Cd%20%3D%5Csqrt%7B%28-15%29%5E%7B2%7D%2B%20%2810%29%5E%7B2%7D%7D%5C%5C%5C%5Cd%20%3D%20%5Csqrt%7B225%2B%20100%7D%5C%5C%5C%5Cd%3D%5Csqrt%7B325%7D%5C%5C%5C%5Cd%3D5%5Csqrt%7B13%7D)
How to Draw Parallel Lines:
1. Draw a straight line any length
2. Draw another straight line any length
(note : ensure the lines will never intersect)
They shall never horizontally or vertically.
How to Draw Perpendicular Lines:
1. Draw a straight line vertically
2. Draw a straight line horizontally
(note : length does not necessarily matter)
The two lines must cross at right angles to each other!!
With the parallel line instructions, simply just draw lines but, when given the slopes of two lines, you must get graphing paper or make your own, and graph it by plotting points and then getting a ruler and tracing it.
With the perpendicular lines it helps with showing a relation between situations along with given slopes. They shall intersect always and meet at a 90° angle. Use the equations and plot them then take a ruler and trace them and notice the intersection. Solve it yourself and see that the intersection and the answers you got are the same.