Seven less than the sum of p and r is as much as 6

1.2x minus 4y equals 28. What does y equal.

seraphim [82]

Answer:

y = 1.2/4 x + 7

Step-by-step explanation

1.2x - 4y =28

4y = 1.2x + 28

y = 1.2/4 x + 28/4

y = 1.2/4 x + 7

4 0

3 years ago

Can anyone please help me? Please please, i need help.

Papessa [141]

Answer:

Step-by-step explanation:

3 0

3 years ago

A boat traveled 147 miles downstream and back. The trip downstream took 7 hours. The trip back took 147 hours. Find the speed of

KonstantinChe [14]

Answer:

The speed of boat in still water is 11 miles per hour

The speed of current is 10 miles per hour .

Step-by-step explanation:

Given as :

The distance cover by boat in downstream = $d_1$ = 147 miles

The time taken by boat in downstream trip = $t_1$ = 7 hours

The distance cover by boat in upstream = $d_2$ = 147 miles

The time taken by boat in upstream trip = $t_2$ = 147 hours

Let The speed of boat in still water = $s_1$ = x mph

And The speed of the current = $s_2$ = y mph

Now, According to question

Speed = $\dfrac{\textrm Distance}{\textrm Time}$

For downstream

$s_1$ + $s_2$ = $\dfrac{d_1}{t_1}$

or, x + y = $\dfrac{147}{7}$

I.e x + y = 21 mph ..........1

For upstream

$s_1$ + $s_2$ = $\dfrac{d_2}{t_2}$

or, x - y = $\dfrac{147}{147}$

I.e x - y = 1 mph ..........2

Now, Solving Eq 1 and 2

I.e (x + y) + (x - y) = 21 + 1

Or, (x + x) + (y - y) = 22

Or, 2 x = 22

∴ x = $\frac{22}{2}$

I.e x = 11 mph

So, speed of boat = x = 11 miles per hour

Again, put The value of x in Eq 2

So, x - y = 1 mph

I.e 11 - y = 1

∴, y = 11 - 1

I.e y = 10 mph

So, speed of current = y = 10 miles per hour

Hence The speed of boat in still water is 11 miles per hour , and The speed of current is 10 miles per hour . Answer

3 0

3 years ago

What appears to be the solution to the system of equations shown in the graph below?

AlladinOne [14]

Given:

The system of equation is,

$3x-4y = -2$ -------- (1)

$-6x+5y = 7$ -------- (2)

To find the solution.

To solve the system of equation,

From (1) we get, $3x = -2+4y$

Putting this value into (2) we get,

$-6x+5y = 7$

or, $-2(3x)+5y = 7$

or, $-2(4y-2)+5y = 7$

or, $-8y+4+5y = 7$

or, $-3y = 7-4$

or, $-3y = 3$

or, $y = -1$

From (1) we get,

$3x = -2+4(-1)$

or, $3x = -6$

or, $x = -2$

Hence,

The solution is $x= -2$ and $y = -1$

6 0

3 years ago

Please help! I’m confused (both questions, 24 & 25) I need to find all of the letters shown and show my work.

svlad2 [7]

Problem 24

<h3>Answer: w = 120</h3>

-----------------

Work Shown:

We have an isosceles triangle. The angles opposite the congruent sides are congruent. These are the base angles each 30 degrees. The missing angle is w. The three angles add to 180

(angle1)+(angle2)+(angle3) = 180

30+30+w = 180

60+w = 180

60+w-60 = 180-60 ... subtract 60 from both sides

w = 120

======================================================

Problem 25

<h3>Answers:</h3><h3>x = 6.5</h3><h3>y = 5</h3>

-----------------

Work Shown:

The angle marks are all the same, so the three angles are congruent to one another. We consider this an equiangular triangle. Any equiangular triangle is also equilateral, meaning all three sides are the same length.

So,

2x-5 = 8

2x-5+5 = 8+5 ... add 5 to both sides

2x = 13

2x/2 = 13/2 ... divide both sides by 2

x = 6.5

and also,

y+3 = 8

y+3-3 = 8-3 ... subtract 3 from both sides

y = 5

3 0

3 years ago