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Kay [80]
3 years ago
7

Suppose that three astronauts outside a spaceship decide to play catch. all three astronauts have the same mass and are equally

strong. the first astronaut throws the second astronaut toward the third one and the game begins. describe the motion of the astronauts as the game proceeds. how long will the game last?
Mathematics
1 answer:
Sloan [31]3 years ago
8 0
<span>Since they are playing in the space, gravity or the lack of it plays a huge role here. When the first astronaut throws the second astronaut toward the third one and due to the force exerted they would be moving in the opposite direction and there won't be any catch. Hence the game does not continue after the first throw.</span>
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5 0
3 years ago
-2(bx - 5) = 16<br><br> What’s does b and x equal?
horrorfan [7]
To solve this problem you must apply the proccedure shown below:
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 <span>-2(bx - 5) = 16
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 When yoo solve for x:
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3 years ago
Solve the following 2 equation.<br>I will Make Brainliest​
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Answer:

d.  x = 10

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Step-by-step explanation:

I've typed up my workings in MS Word and attached them (as it's very difficult to type this in the Brainly equation editor).

I've used the product, quotient and power log laws.

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2 years ago
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Sauron [17]

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