Answer:
2 vertical asymptotes occurring at x = 5 and x = -1
Step-by-step explanation:
given
recall that asymptotic occur at the locations that will make the equation undefined. In this case, the asymptote will occur at x-locations which will cause the denominator to become zero (and hence undefined)
Equating the denominator to zero,
(x-5)(x+1) = 0
(x-5) =0
x = 5 (first asymptote)
or (x+1) = 0
x = -1 (2nd asymptote)
Answer:
Step-by-step explanation:
<u><em>Solving equation A: y = x </em></u>
Let us consider the given equation A:
y = x
y = x
y = 1 ∵ x = 1
Hence, (1, 1) is the ordered pair of y = x
y = x
y = 2 ∵ x = 2
Hence, (2, 2) is the ordered pair of y = x
y = x
y = 3 ∵ x = 3
Hence, (3, 3) is the ordered pair of y = x
y = x
y = 4 ∵ x = 4
Hence, (4, 4) is the ordered pair of y = x
y = x
y = 5 ∵ x = 5
Hence, (5, 5) is the ordered pair of y = x
Lets us consider all the ordered pairs i.e. (1, 1), (2, 2), (3, 3), (4, 4) and (5, 5) to make a table for y = x.
<em>y x</em>
1 1
2 2
3 3
4 4
5 5
As from the table, lets take the ratio of every point i.e. y/x
Hence, the ratio for all the points on the equation y = x is same. Hence, the equation y = x REPRESENTS a proportional relationship. Please also check the graph in attached<em> figure a.</em>
<u><em>Solving equation A: y = x +2</em></u>
Let us consider the given equation A:
y = x + 2
y = x + 2
y = 1 + 2 ⇒ 3 ∵ x = 1
Hence, (1, 3) is the ordered pair of y = x + 2
y = x + 2
y = 2 +2 ⇒ 4 ∵ x = 2
Hence, (2, 4) is the ordered pair of y = x + 2
y = x + 2
y = 3 + 2 ⇒ 5 ∵ x = 3
Hence, (3, 5) is the ordered pair of y = x + 2
y = x + 2
y = 4 + 2 ⇒ 6 ∵ x = 4
Hence, (4, 6) is the ordered pair of y = x + 2
y = x + 2
y = 5 +2 ⇒ 7 ∵ x = 5
Hence, (5, 7) is the ordered pair of y = x + 2
Lets us consider all the ordered pairs i.e. (1, 3), (2, 4), (3, 5), (4, 6) and (5, 7) to make a table for y = x + 2.
<em>y x + 2</em>
1 3
2 4
3 5
4 6
5 7
As from the table, lets take the ratio of every point i.e. y/x
Hence, the ratio for all the points on the equation y = x+2 is not same. Hence, the equation y = x + 2 DOES NOT REPRESENT a proportional relationship. Please also check the graph in attached<em> figure a.</em>
<em>Keywords: equation, graph</em>
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