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3 years ago

Replace the ? with one of the following symbols (<, >, =, or ≠) for 2 + 3 ? 4 + 1 A. ≠ B. = C. > D.

Mathematics

2 answers:

vova2212 [387]3 years ago

6 0

= the ? is = because when you add both u get an equal amount

Agata [3.3K]3 years ago

3 0

Answer:

The answer is the option B

The symbol is equal $(=)$

Step-by-step explanation:

we have

$2+3 ? 4+1$

Solve the right side

$4+1=5$

Solve the left side

$2+3=5$

the right side is equal to the left side

therefore

The answer is the symbol equal $(=)$

$2+3 = 4+1$

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2 years ago

Possible solution for 4+x+2-2x=5

MrRissso [65]

Answer:

x=1

Step-by-step explanation:

For algebra always start by rewriting it.

4+x+2-2x=5

Then ask yourself is there any like terms we can combine, and here yes there is. 4 and 2 and x and -2x. Now lets combine them and rewrite.

6-x=5

Now lets get x alone and the quickest way is to subtract 6 to the other side

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Your answer is

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3 years ago

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Answer:

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Step-by-step explanation:

I think this is right

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2 years ago

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2 years ago

A car insurance company has determined that 8% of all drivers were involved in a car accident last year. Among the 15 drivers li

svetlana [45]

Answer:

There is an 11.3% probability of getting 3 or more who were involved in a car accident last year.

Step-by-step explanation:

For each driver surveyed, there are only two possible outcomes. Either they were involved in a car accident last year, or they were not. This means that we solve this problem using binomial probability concepts.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

In this problem

15 drivers are randomly selected, so $n = 15$ .

A success consists in finding a driver that was involved in an accident. A car insurance company has determined that 8% of all drivers were involved in a car accident last year. This means that $\pi = 0.08$ .

What is the probability of getting 3 or more who were involved in a car accident last year?

This is $P(X \geq 3)$ .

Either less than 3 were involved in a car accident, or 3 or more were. Each one has it's probabilities. The sum of these probabilities is decimal 1. So:

$P(X < 3) + P(X \geq 3) = 1$