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jekas [21]
3 years ago
5

Isla’s change in velocity is 30 m/s, and Hazel has the same change in velocity. Which best explains why they would have differen

t accelerations?
Isla had negative acceleration, and Hazel had positive.
Isla had a different time than Hazel.
Isla had positive acceleration, and Hazel had negative.
Isla went a farther distance than Hazel.
Mathematics
1 answer:
sergiy2304 [10]3 years ago
6 0

Answer:

B  have a wonderful week d remember God loves u and Merry Christmas

Step-by-step explanation:

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(8.18x10^-6)(1.15x10^-5)
ladessa [460]

Answer:

9.407x10-11

Step-by-step explanation:

8.18(9.407x(10)−11)10−6(1.15(9.407x(10)−11)10−5)

8.18(9.407x(10)−11)10−6(1.15(9.407x(10)−11)10−5)

8 0
3 years ago
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What are the solutions of the equation x^3-x=0?
lana66690 [7]
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4 years ago
How do I find a2 and a3 for the following geometric sequence? 54, a2, a3, 128
vlada-n [284]
The formula for the nth term of a geometric sequence:
a_n=a_1 \times r^{n-1}
a₁ - the first term, r - the common ratio

54, a_2, a_3, 128 \\ \\
a_1=54 \\
a_4=128 \\ \\
a_n=a_1 \times r^{n-1} \\
a_4=a_1 \times r^3 \\
128=54 \times r^3 \\
\frac{128}{54}=r^3 \\ \frac{128 \div 2}{54 \div 2}=r^3 \\
\frac{64}{27}=r^3 \\
\sqrt[3]{\frac{64}{27}}=\sqrt[3]{r^3} \\
\frac{\sqrt[3]{64}}{\sqrt[3]{27}}=r \\
r=\frac{4}{3}

a_2=a_1 \times r= 54 \times \frac{4}{3}=18 \times 4=72 \\
a_3=a_2 \times r=72 \times \frac{4}{3}=24 \times 4=96 \\ \\
\boxed{a_2=72, a_3=96}
7 0
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How to solve this equation?
lilavasa [31]
I solved it on your other posting of it. x = 12
All of the steps are there
7 0
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Show work please <br><br> A 18 <br> B 2<br> C 9 <br> D 1
NeTakaya

Answer:

a

Step-by-step explanation:

the need to equal the same and none of the lower numbers work

6 0
3 years ago
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