Answer:
2nd graph
Step-by-step explanation:
Given
f(x) = x² + 3x - 4
To find the zeros let f(x) = 0 , that is
x² + 3x - 4 = 0 ← in standard form
(x + 4)(x - 1) = 0 ← in factored form
Equate each factor to zero and solve for x
x + 4 = 0 ⇒ x = - 4
x - 1 = 0 ⇒ x = 1
The only graph with zeros at x = - 4 and x = 1 is the 2nd graph
Base or base number
for example 2^3 = 2 * 2 * 2 or x^2 = x * x
Answer: The answer is 8.
Step-by-step explanation: The first step is to convert the expression into figures. We shall call the unknown number Y. So if we are told “the square of a number,” that means Y squared, or better still, Y^2. Further we are told “the difference between the square of a number and 40” and that can be written as;
Y^2 - 40.
Next we are told that this expression is equal to 3 times that number (that is 3Y). That can now be written out as follows,
Y^2 - 40 = 3Y
If we move all expressions to one side of the equation, what we would have is,
Y^2 - 3Y -40 = 0
(Remember that when a positive value crosses to the other side of an equation it becomes negative and vice versa)
We now have a quadratic equation
Y^2 -3Y - 40 = 0
By factorizing we now have
(Y -8) (Y + 5) = 0
Therefore Y - 8 = 0 or
Y + 5 = 0
Hence, Y = 8 or Y = -5
Since we are asked to calculate the positive solution, Y = 8
(a^2)^4 = a^8, and (b^3)^4 = b^12. Thus, the quotient is
a^8
--------
b^12
Answer:
hope this helps.
Step-by-step explanation:
You don't really need to get them in the y format.
make a table and plug some numbers in and graph those points
use a ruler to connect the dots.
y = -3 is a horizontal line
