Question

2+8+32+128…..,n=9 Evaluate each geometric series described

Answer 1

The value of 2+8+32+128…..,n=9 is 174762

How to evaluate the series?

The series is given as:

2+8+32+128…..,n=9

Start by calculating the common ratio (r)

r = 8/2

r = 4

The sum of the series is then calculated as:

$S_n = \frac{a *(r^n - 1)}{r -1}$

This gives

$S_9 = \frac{2 *(4^9 - 1)}{4 -1}$

Evaluate the difference

$S_9 = \frac{2 *( 262143)}{3}$

Evaluate the quotient

$S_9 = 174762$

Hence, the value of 2+8+32+128…..,n=9 is 174762

Read more about series at:

brainly.com/question/7882626

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