2 years ago

2+8+32+128…..,n=9 Evaluate each geometric series described

Mathematics

1 answer:

DedPeter [7]2 years ago

6 0

The value of 2+8+32+128…..,n=9 is 174762

<h3>How to evaluate the series?</h3>

The series is given as:

2+8+32+128…..,n=9

Start by calculating the common ratio (r)

r = 8/2

r = 4

The sum of the series is then calculated as:

$S_n = \frac{a *(r^n - 1)}{r -1}$

This gives

$S_9 = \frac{2 *(4^9 - 1)}{4 -1}$

Evaluate the difference

$S_9 = \frac{2 *( 262143)}{3}$

Evaluate the quotient

$S_9 = 174762$

Hence, the value of 2+8+32+128…..,n=9 is 174762

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