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Mamont248 [21]
1 year ago
11

Can the sides of a triangle have lengths 2, 4, and 7?

Mathematics
2 answers:
crimeas [40]1 year ago
5 0
Yes. It would be a scalene triangle.

However, a right triangle cannot have those lengths (because if we inputted the values into the Pythagorean Theorem, it wouldn’t be a true equation).


Hope this helps! (:
LekaFEV [45]1 year ago
4 0

Answer:

No, they can't

Step-by-step explanation:

According to the Triangle Inequality Theorem, the largest side cannot be greater than the sum of the other two sides.

2+4= 6<7

As you can see from this Equation NOT any two side are greater than the third making this NOT possibly be a tringle.

2+7=9>4

4+7=11>2

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How can you simplify 24 to 96 ​
Nezavi [6.7K]

Step-by-step explanation:

Reduce 24/96 to lowest terms

Find the GCD (or HCF) of numerator and denominator. GCD of 24 and 96 is 24.

24 ÷ 2496 ÷ 24.

Reduced fraction: 14. Therefore, 24/96 simplified to lowest terms is 1/4.

7 0
2 years ago
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Solve the system of equations 2r + 2s = 50 and 2r – s = 17. A. r = 3, s = 11 B. r = 25, s = 33 C. r = 14, s = 11 D. r = –8, s =
scZoUnD [109]

2r = 17 + s = 50 - 2s \\ 3s = 50 - 17 = 33 \\ s = 11 \\  \\2 r = 50 - 2s \\ 2r = 50 - 2 \times 11 = 50 - 22 = 28 \\ r = 14




C. r=14, s =11
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3 years ago
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Murljashka [212]
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3 0
3 years ago
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Lapatulllka [165]

Answer:

CD=4 \text{ cm }

Step-by-step explanation:

We have a similarity of triangles. Once the side BC and ED are parallel,

$\frac{BC}{AC} =\frac{ED}{AD} $

$\frac{10}{AC} =\frac{5}{4} $

Once AC=AD+CD \Rightarrow AC=4+CD

$\frac{10}{4+CD} =\frac{5}{4} $

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6 0
3 years ago
Create an equation to solve for x using the trapezoid midsegment formula:
Serggg [28]

Answer:

Equation for x:    3x - 6 = \frac{2x - 1 + 25}{2}

x = 9

CD = 17

GH = 21

Step-by-step explanation:

The midsegment formula for a trapezoid is

GH = \frac{CD + FE}{2}

3x - 6 = \frac{2x - 1 + 25}{2}

6x - 12 = 2x + 24

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GH = 3x - 6 = 3(9) - 6 = 3 = 27 - 6 = 21

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3 years ago
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