1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
IgorLugansk [536]
3 years ago
15

The length of a rectangle is x times the square root of 100. The width is one-half y more than three-halves x. Given that the ar

ea of the rectangle is 125 cm2, formulate an equation to represent the rectangle in terms of x and y?
Mathematics
2 answers:
dimulka [17.4K]3 years ago
7 0

Answer:

15x^2+5xy-125=0

Step-by-step explanation:

We are give the following in the question:

Dimensions of rectangle:

Length , l =

l = x\sqrt{100} = 10x

Width of rectangle, w =

w = \dfrac{y}{2} +\dfrac{3x}{2}

Area of rectangle = 125 square cm.

Area of rectangle =

A =l\times w

Putting values, we get,

125 = 10x\times (\dfrac{y}{2}+\dfrac{3x}{2})\\\\125 = 5xy+15x^2\\15x^2+5xy-125=0

is the required equation.

faust18 [17]3 years ago
4 0

Answer:

The user before me has the right answer : 15x2 + 5xy = 125

Step-by-step explanation:

You might be interested in
In a right triangle ABC, CD is an altitude, such that AD=BC. Find AC, if AB=3 cm, and CD= 2 cm.
konstantin123 [22]

Consider right triangle ΔABC with legs AC and BC and hypotenuse AB. Draw the altitude CD.

1. Theorem: The length of each leg of a right triangle is the geometric mean of the length of the hypotenuse and the length of the segment of the hypotenuse adjacent to that leg.

According to this theorem,

BC^2=BD\cdot AB.

Let BC=x cm, then AD=BC=x cm and BD=AB-AD=3-x cm. Then

x^2=(3-x)\cdot 3,\\ \\x^2=9-3x,\\ \\x^2+3x-9=0,\\ \\D=3^2-4\cdot (-9)=9+36=45,\\ \\\sqrt{D}=\sqrt{45}=3\sqrt{5},\\ \\x_1=\dfrac{-3-3\sqrt{5} }{2}0.

Take positive value x. You get

AD=BC=\dfrac{-3+3\sqrt{5} }{2}\ cm.

2. According to the previous theorem,

AC^2=AD\cdot AB.

Then

AC^2=\dfrac{-3+3\sqrt{5} }{2}\cdot 3=\dfrac{-9+9\sqrt{5} }{2},\\ \\AC=\sqrt{\dfrac{-9+9\sqrt{5} }{2}}\ cm.

Answer: AC=\sqrt{\dfrac{-9+9\sqrt{5} }{2}}\ cm.

This solution doesn't need CD=2 cm. Note that if AB=3cm and CD=2cm, then

CD^2=AD\cdot DB,\\ \\2^2=AD\cdot (3-AD),\\ \\AD^2-3AD+4=0,\\ \\D

This means that you cannot find solutions of this equation. Then CD≠2 cm.

8 0
3 years ago
Read 2 more answers
Gisele went to the shoe store and bought two pairs of flats. One pair was $21.20, and the other was $31.50. If she has $60.00, h
Andrei [34K]
$8.30?

I need more info, is this including tax or are you having to tax the items as well?
5 0
3 years ago
Read 2 more answers
George has a mass of 65kg. What would George weigh on the Moon? (The gravitational field strength on the Moon is 1.6N/kg.)
maks197457 [2]

George would weigh

65 kg × 1.6N /kg = 104 Newtons

That's compared to around 650 Newtons on earth.

3 0
3 years ago
Read 2 more answers
67.1 minus 38.29 = <br> A. -105.39 <br> B. 28.81 <br> C. -28.81 <br> D. -44.352
zalisa [80]
67,1 - 38,29 = 28,81

B

5 0
3 years ago
Can u please find the length of BC round to the nearest tenth
PolarNik [594]

Answer:

Step-by-step explanation:

Using sine rule

SinA/a = SinB/b = SinC/c

A = 84° a = BC, C = 51°, c = 16

Sin84/BC = Sin51/16

Cross multiply

BC Sin51 = 16 × Sin84

BC = 15.91/Sin51

BC = 20.48unit

5 0
3 years ago
Other questions:
  • Write a quadratic function in vertex form whose graph has the vertex (−5, −1) and passes through the point (−2, 2)
    15·1 answer
  • Factor the expression completely 8y - 36
    11·2 answers
  • Help me asap :3...........
    13·1 answer
  • What is x in 2(x+6)=14
    13·1 answer
  • What is the event space for rolling a number greater than 1 with one die
    6·2 answers
  • Joyce paid $230 for an item at the store that was 20% off the original price. What was the original price?
    15·2 answers
  • 1. Which scatterplot suggests a linear relationship between x and y?
    13·1 answer
  • Help me on this question someone
    8·2 answers
  • the summer camps had a field trip from the campus to fragrance hill. they traveled at an average speed of 65km/h in the first tw
    10·1 answer
  • A face of a solid is
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!