Simplify as much as possible. 2w?V32wu? + u V 18w5 ?
1 answer:
Answer:
Step-by-step explanation:
I'm never sure how far to go on these questions but I think what I'e done looks pretty nice. Essentially I simplified each radical, factored out each variable, combined the radicals after more simplification, and then picked the answer you were most likely looking for. I gave some alternatives in my work that are "simple" too, but the answer above is most likely I'd say.
Work is in the attachment, comment with any questions.
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The area of the surface is given exactly by the integral,
We have
so the area is
We split up the domain of integration into 10 subintervals,
[0, 1/2], [1/2, 1], [1, 3/2], ..., [4, 9/2], [9/2, 5]
where the left and right endpoints for the -th subinterval are, respectively,
with midpoint
with .
Over each subinterval, we interpolate with the quadratic polynomial,
Then
It turns out that the latter integral reduces significantly to
which is about 651.918, so that the area is approximately .
Compare this to actual value of the integral, which is closer to 1967.