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Leni [432]
2 years ago
10

3 + 2 x 7 - 30(^2) help me

Mathematics
1 answer:
shepuryov [24]2 years ago
3 0
There is no solution to this problem. Why? Well, see below for an explanation!

We can initially solve this problem using PEMDAS. Where we go wrong will be identified later. The P stands for Parenthesis, but there are none in this equation so we can skip that step. Next is E, which stands for Exponents. We do have an exponent, but it is separate from the problem. That would deem the problem invalid to solve because there is no base number for the exponent to be solved. Disregarding the exponent, we can solve by using M, which means Multiplication.

2 x 7 = 14

Next step, we can simplify to make the equation a tad bit neater.

3 + 14 - 30

Next up is D, meaning we need to divide. There are no numbers to divide though, so this step can be skipped.

Next step would be A, meaning we need to add.
3 + 14 = 17

Next step, we can simplify to make the equation neater as stated above.

17 - 30

17 - 30 = -13.

Disregarding the exponent, your answer would be -13. Including the exponent, however, would make the equation irrelevant. If you need extra help understanding this, let me know and I will gladly assist you.
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The triangles below are similar. Triangle A B C. Side A C is 10 and side A B is 5. Angle C is 30 degrees. Triangle D E F. Side E
Gnoma [55]

Answer:

\triangle ABC {\displaystyle \sim } \triangle DE\ F

\triangle CBA {\displaystyle \sim } \triangle FED

\triangle BAC {\displaystyle \sim } \triangle EDF

Step-by-step explanation:

Given

\triangle ABC {\displaystyle \sim } \triangle DE\ F

AC = 10

AB = 5

\angle C = 30^\circ

ED = 7.5

DF = 25

\angle F =30

\angle E =90

Required

Which of the options is/are true:

\triangle CBA {\displaystyle \sim } \triangle FED            \triangle CBA {\displaystyle \sim } \triangle FDE              \triangle BAC {\displaystyle \sim } \triangle EFD

\triangle BAC {\displaystyle \sim } \triangle EDF            \triangle ABC {\displaystyle \sim } \triangle DE\ F             \triangle ABC {\displaystyle \sim } \triangle DFE

The given triangles, implies that:

A {\displaystyle \sim } \ D

B {\displaystyle \sim } \ E

C {\displaystyle \sim } \ F

By taking each sides of both triangle, one after the other; the possible similar triangles are:

\triangle ABC {\displaystyle \sim } \triangle DE\ F

\triangle CBA {\displaystyle \sim } \triangle FED

\triangle BAC {\displaystyle \sim } \triangle EDF

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de fk?

Step-by-step explanation:

wth is that

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4. The red graph (1) is the graph of f(x) = log(x). Describe the transformation of the blue function (2) and write the equation
sergey [27]

Answer:

Function f(x) is shifted 1 unit left and 1 unit up.

f(x)\rightarrow f(x+1)+1

Transformed function f(x+1)+1=\log(x+1)+1

Step-by-step explanation:

Given:

Red graph (Parent function):

f(x)=\log(x)

Blue graph (Transformed function)

From the graph we can see that the red graph is shifted 1 units left and 1 units up.

Translation Rules:

f(x)\rightarrow f(x+c)

If c>0 the function shifts c units to the left.

If c the function shifts c units to the right.

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If c the function shifts c units to the down.

Applying the rules to f(x)

The transformation statement is thus given by:

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As function f(x) is shifted 1 unit left and 1 unit up.

Transformed function is given by:

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