As is the case for any polynomial, the domain of this one is (-infinity, +infinity).
To find the range, we need to determine the minimum value that f(x) can have. The coefficients here are a=2, b=6 and c = 2,
The x-coordinate of the vertex is x = -b/(2a), which here is x = -6/4 = -3/2.
Evaluate the function at x = 3/2 to find the y-coordinate of the vertex, which is also the smallest value the function can take on. That happens to be y = -5/2, so the range is [-5/2, infinity).
Answer:
The prime factors are: 2 x 2 x 59
or Written in exponential form: 2^2 x 59^1
Step-by-step explanation:
236 ÷ 2 = 118 - No remainder! 2 is one of the factors
118 ÷ 2 = 59 - No remainder! 2 is one of the factors
59 ÷ 59 = 1 - No remainder! 59 is one of the factors
together we have the factors 2 x 2 x 59 = 236
Answer:
Required difference = 270/19 km
Step-by-step explanation:
If we consider the AP of distances to be
a, a + r, a + 2r, ..., a + 19r,
where a is the distance of the nearest location from the port and r is the difference between any two successive location.
Given that,
a + 19r = 300 .....(1)
a = 30 ..... (2)
Using (2), from (1), we get
30 + 19r = 300
or, 19r = 300 - 30
or, 19r = 270
or, r = 270/19
Therefore the distance between any two successive location is 270/19 km.
Answer:
10y^3+6y
Step-by-step explanation:
