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3 years ago

What is the equation of the parabola with vertex (-2,5) and an x-intercept of x = 3

Mathematics

1 answer:

Maslowich3 years ago

3 0

Step-by-step explanation:

if parabola has a vertex not in x-axis, it should have 2 x intercept

x-vertex = -2

first x intercept = 3

second x intercept should -7

so the equation will like this

y = a(x-x1)(x-x2)

y = a (x-3)(x+7)

y = a(x² + 4x - 21)

5 = a((-2)² + 4(-2) - 21)

5 = a(4 - 8 - 21)

5 = a(-25)

a = 5/(-25)

a = -1/5

then the equation is

y = (-1/5)(x² - 4x - 21)

or you can write as

y = -x²/5 + 4x/5 + 21/5

or as this one

5y = -x² + 4x + 21

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25%

Step-by-step explanation:

she earned $1,000

she spent $250

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3 years ago

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What are zeros of the function? What are there multiples? f(x) = 4x^3 -20x2 + 24x

bixtya [17]

When X=0, the function would be:

f(x) = 4x^3 -20x2 + 24x
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x(4x^2 -12x -8x + 24)
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x1= 0
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3 years ago

Point T has coordinates (10,20). To calculate the coordinates of point T′ in the image,

Hatshy [7]

Answer: $T'(18,36)$

Step-by-step explanation:

For this exercise it is important to know the definition of "Dilation".

A Dilation is defined as a transformation in which the Image (The figure obtained after the transformation) and the Pre-Image (The original figure before the transformation) have the same shape but have different sizes.

If the Dilation is centered at the origin, and knowing the scale factor of $\frac{9}{5}$ , you need to multiply each coordinate of the point T by the scale factor in order to find the coordinates of the Image T'.

Knowing that the point T has the following coordinates:

$T(10,20)$

You get that the coordinates of the Image T' are the shown below:

$T'=(\frac{9}{5}*10,\frac{9}{5}*20)\\\\T'=(18,36)$

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3 years ago

Giving 100 points.

Nitella [24]

Answer:

1. Cost per customer: 10 + x

Average number of customers: 16 - 2x

$\textsf{2.} \quad -2x^2-4x+160\geq 130$

3. $10, $11, $12 and $13

Step-by-step explanation:

Given information:

$10 = cost of buffet per customer
16 customers choose the buffet per hour
Every $1 increase in the cost of the buffet = loss of 2 customers per hour
$130 = minimum revenue needed per hour

Let x = the number of $1 increases in the cost of the buffet

Part 1

Cost per customer: 10 + x

Average number of customers: 16 - 2x

Part 2

The cost per customer multiplied by the number of customers needs to be at least $130. Therefore, we can use the expressions found in part 1 to write the inequality:

$(10 + x)(16 - 2x)\geq 130$

$\implies 160-20x+16x-2x^2\geq 130$

$\implies -2x^2-4x+160\geq 130$

Part 3

To determine the possible buffet prices that Noah could charge and still maintain the restaurant owner's revenue requirements, solve the inequality:

$\implies -2x^2-4x+160\geq 130$

$\implies -2x^2-4x+30\geq 0$

$\implies -2(x^2+2x-15)\geq 0$

$\implies x^2+2x-15\leq 0$

$\implies (x-3)(x+5)\leq 0$

Find the roots by equating to zero:

$\implies (x-3)(x+5)=0$

$x-3=0 \implies x=3$

$x+5=0 \implies x=-5$

Therefore, the roots are x = 3 and x = -5.

Test the roots by choosing a value between the roots and substituting it into the original inequality:

$\textsf{At }x=2: \quad -2(2)^2-4(2)+160=144$

As 144 ≥ 130, the solution to the inequality is between the roots:

-5 ≤ x ≤ 3

To find the range of possible buffet prices Noah could charge and still maintain a minimum revenue of $130, substitute x = 0 and x = 3 into the expression for "cost per customer.

[Please note that we cannot use the negative values of the possible values of x since the question only tells us information about the change in average customers per hour considering an increase in cost. It does not confirm that if the cost is reduced (less than $10) the number of customers increases per hour.]

Cost per customer:

$x =0 \implies 10 + 0=\$10$