Answer:
29.4 meters
Step-by-step explanation:
Given the following :
A submarine ascended from 56.8 meters under the sea level to 27.4 meters under the sea level.
distance it moved between two positions. Use the "distance on the number line "formula
Initial Position or distance of submarine before ascension = 56.8 meters
Final position after ascension = 27.4 meters
The distance moved by the submarine between the two positions can be obtained by.
(Initial distance - Final distance)
(56.8 - 27.4) = 29.4 meters
You will find the area the square and then find out what 4/5 of that area is.
A = bh
6 cm x 6 cm
A = 36 square cm
4/5 of 36 square cm
4/5 x 36
28 4/5 square cm
The area of the rhombus is 28 4/5 square cm. Use this to solve for the height of the rhombus.
A = bh
<u>28 4/5</u> = <u>6 x h</u>
6 6
h = 4 4/5 cm
The height of the rhombus is 4 4/5 cm.
Colfax:
Add the ratio numbers together:
5 + 4 = 9
Divide total students by that:
270 / 9 = 30
Multiply each ratio by 30:
Boys = 30 *5 = 150
Girls = 30 * 4 = 120
Do the same for Winthrop:
4 +5 = 9
180 /9 = 20
Boys = 20 * 4 = 80
Girls = 20 * 5 = 100
Total students = 270 + 180 = 450
Total Girls = 120 + 100 = 220
Fraction that are girls = 220 / 450 which reduces to 22/45
