Answer:
30 m/s
Step-by-step explanation:
<em>p = mv</em>
<em>momentum</em><em> </em><em>=</em><em> </em><em>mass</em><em> </em><em>×</em><em> </em><em>velocity</em>
<em>here</em><em> </em><em>the</em><em> </em><em>momentum</em><em> </em><em>is</em><em> </em><em>60kgm</em><em>/</em><em>s</em>
<em>mass</em><em> </em><em>is</em><em> </em><em>2kg</em>
<em>substitute</em><em> </em><em>in</em><em> </em><em>the</em><em> </em><em>equation</em>
<em>6</em><em>0</em><em> </em><em>=</em><em> </em><em>2v</em>
v= 30m/s
We're looking for the two values being subtracted here. One of these values is easy to find:
<span>g(1) = ∫f(t)dt = 0</span><span>
since taking the integral over an interval of length 0 is 0.
The other value we find by taking a Left Riemann Sum, which means that we divide the interval [1,15] into the intervals listed above and find the area of rectangles over those regions:
</span><span>Each integral breaks down like so:
(3-1)*f(1)=4
(6-3)*f(3)=9
(10-6)*f(6)=16
(15-10)*f(10)=10.
So, the sum of all these integrals is 39, which means g(15)=39.
Then, g(15)-g(1)=39-0=39.
</span>
I hope my answer has come to your help. God bless and have a nice day ahead!
Step-by-step explanation:
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