Given the length of the two diagonals of the kite, the area of kite ABDC is 33 squared centimeters.
<h3>What is the area of kite ABDC?</h3>
Formular for the area of a kite is expressed as;
A = pq/2
Where p and q are the two diagonals of the kite.
Given the data in the question;
- Diagonal p = line BC = BM + MC = 3 + 3 = 6
- Diagonal q = line AD = AM + MD
- Line AM = ?
- Line MD = ?
From the diagram, we can determine line AM and line MD using Pythagoras theorem.
c² = a² + b²
First, we find line AM
c² = a² + b²
5² = 3² + b²
25 = 9 + b²
b² = 25 - 9
b² = 16
b = √16
b = 4
Line AM = 4
Next, we determine Line MD
c² = a² + b²
(√58)² = 3² + b²
58 = 9 = b²
b² = 58 - 9
b² = 49
b = √49
b = 7
Line MD = 7
Now, we can find the area of the kite.
Diagonal p = BC = 6
Diagonal q = AD = AM + MD = 4 + 7 = 11
Area = pq/2
Area = [ 6 × 11 ]/2
Area = 66 / 2
Area = 33cm²
Given the length of the two diagonals of the kite, the area of kite ABDC is 33 squared centimeters.
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